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3 years ago

5

Suppose the number 1155 is written as the product of three positive integers. What is the smallest possible value of the sum of

those three integers?

1 answer:

ozzi3 years ago

6 0

3. the equation I used is: 3×5×77

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Solve this: -11<-x+2<8. <br><br> ?

Rufina [12.5K]

You add 2 to each of the three sides.

okay?

-11< -x+2< 8
-2 -2 -2
--------------------
-13< -x <2
Divide by negative 1

-13< -x <2
--------------
-1
Switch the signs direction

13> x > -2

tada

5 0

3 years ago

Sameer chose 12 different toppings for his frozen yogurt sundae, which was Three-fourths of the total number of different toppin

Anna71 [15]

Answer: B. Sameer did not use the correct equation

<u>Step-by-step explanation:</u>

12 IS three-fourths OF x

IS: equals

OF: multiplication

$12=\dfrac{3}{4}x$

48 = 3x

16 = x

8 0

4 years ago

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HELP please ASAP!!!!!

ololo11 [35]

The third one I think btw if you get mad at this person

8 0

3 years ago

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The following estimated regression equation based on 30 observations was presented. ŷ = 17.6 + 3.8x1 − 2.3x2 + 7.6x3 + 2.7x4 The

trapecia [35]

Answer:

a) = 0.9739

b) = 0.969

c) option A is correct

Step-by-step explanation:

Given that:

sample size n = 30

SST = 1803

SSR = 1756

$R^2 = \dfrac{SSR}{SST} \\ \\ R ^2 = \dfrac{1756}{1803} \\ \\ \mathbf{R^2 =0.9739}$

The adjusted $R_a^2$ is computed as:

$R_a^2 = 1 - (\dfrac{n-1}{n-p})(1-R^2)$

where;

$p = k+1 \\ p= 4+1 = 5$

$R_a^2 = 1 - (\dfrac{30-1}{30-5})(1-0.9739)$

$R_a^2 = 1 - (\dfrac{29}{25})(0.0261)$

$R_a^2 = 1 - (1.16)(0.0261)$

$R_a^2 = 1 -0.030276$

$\mathbf{R_a^2 \simeq 0.969}$

7 0

3 years ago

In a class, two out of every 10 students fails. If there are 50 students in the class, how many pass the test

Alexandra [31]

Step-by-step explanation:

$thank \: you$

8 0

3 years ago

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