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Fiesta28 [93]
3 years ago
9

Solve (x+y) if x=-1/2 and y=-3

Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer:

-3\frac{1}{2}

Step-by-step explanation:

Solve

(x+y)

For x=-1/2 and y=-3

substitute the value of x and the value of y in the expression above

x+y=(-\frac{1}{2})+(-3)

Remember that

(+1)(-1)=-1

so

x+y=-\frac{1}{2}-3=\frac{-1-6}{2}=-\frac{7}{2}

Convert to mixed number

-\frac{7}{2}=-\frac{6}{2}-\frac{1}{2}=-3\frac{1}{2}

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Given right triangle MNL, what is the value of cos(M)? Three-fifths Three-fourths Four-fifths Five-thirds
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By applying the Pythagorean Theorem and the Trigonometry ratio, CAH, the value of cos(M) = 4/5

<em><u>Recall:</u></em>

Trigonometry ratios, <em>SOH CAH TOA</em> can be applied to solve a right triangle.

  • Pythagorean Theorem can also be applied which is: c² = b² + a², where c is the longest side (hypotenuse length).

<em><u>Given:</u></em>

ΔMNL is a right triangle

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Find MN using the Pythagorean Theorem:

MN = √(ML² - NL²)

MN = √(25² - 15²)

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