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3 years ago

Solve (x+y) if x=-1/2 and y=-3

Mathematics

1 answer:

bixtya [17]3 years ago

7 0

Answer:

$-3\frac{1}{2}$

Step-by-step explanation:

Solve

$(x+y)$

For x=-1/2 and y=-3

substitute the value of x and the value of y in the expression above

$x+y=(-\frac{1}{2})+(-3)$

Remember that

$(+1)(-1)=-1$

$x+y=-\frac{1}{2}-3=\frac{-1-6}{2}=-\frac{7}{2}$

Convert to mixed number

$-\frac{7}{2}=-\frac{6}{2}-\frac{1}{2}=-3\frac{1}{2}$

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Multiply the -3 by what is inside the parentheses.
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3 0

3 years ago

Read 2 more answers

A bag of flour weighs 15 kg. A baker has one bag of flour. She uses 1.065 kg every day. How much flour does she use in 8 days? H

Len [333]

Answer:

She uses 8.52 kgs of flour in 8 days

There are 6.48 kgs of flour left over after 8 days.

Step-by-step explanation:

First, you need to multiply 1.065 by 8 to get how much flour she uses in 8 days.

1.065 times 8 is 8.52. She uses 8.52 kgs of flour in 8 days.

Now, to get how much flour is left over after 8 days, you need to subtract 8.52 from 15 kgs.

15 - 8.52 = 6.48 kgs.

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3 years ago

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Ksivusya [100]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

Natalia drove to her grandmother’s house for Thanksgiving. It took her 5 hours, for a total of 225 miles. What is her average sp

Ann [662]

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Step-by-step explanation:

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5 0

3 years ago

Given f(x)=2x^2+3x-5 for what values of x is f(x) positive

kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

$f(x)=2x^{2}+3x-5$

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

$f(x)=2(x^{2}+\frac{3}{2}x)-5$

Complete the square

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}$

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}$

Rewrite as perfect squares

$f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}$

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

$2(x+\frac{3}{4})^{2}-\frac{49}{8}=0$

$2(x+\frac{3}{4})^{2}=\frac{49}{8}$

$(x+\frac{3}{4})^{2}=\frac{49}{16}$

take the square root both sides

$x+\frac{3}{4}=\pm\frac{7}{4}$

$x=-\frac{3}{4}\pm\frac{7}{4}$

$x_1=-\frac{3}{4}+\frac{7}{4}=1$

$x_2=-\frac{3}{4}-\frac{7}{4}=-2.5$

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0

4 years ago