Answer:
a=1/12
Step-by-step explanation:
12a-12=-11
12a=-11+12
12a=1
a=1/12 or .0833333 repeating
9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
Answer:
33
Step-by-step explanation:
Answer:
Number of year to get $10,000 as interest = 7.5 year (Approx)
Step-by-step explanation:
Given:
Initial investment = $20,000
Interest on investment = $10,000
Rate of interest = 5.6% = 0.056
Find:
Number of year to get $10,000 as interest:
Computation:
![Interest\ on\ investment = Initial\ investment[(1+r)^n-1]\\\\10,000 = 20,000[(1+0.056)-1]\\\\0.5=(1.056)^n-1\\\\1.5 =(1.056)^n\\\\n=7.44](https://tex.z-dn.net/?f=Interest%5C%20on%5C%20investment%20%3D%20Initial%5C%20investment%5B%281%2Br%29%5En-1%5D%5C%5C%5C%5C10%2C000%20%3D%2020%2C000%5B%281%2B0.056%29-1%5D%5C%5C%5C%5C0.5%3D%281.056%29%5En-1%5C%5C%5C%5C1.5%20%3D%281.056%29%5En%5C%5C%5C%5Cn%3D7.44)
Number of year to get $10,000 as interest = 7.44
Number of year to get $10,000 as interest = 7.5 year (Approx)
Answer:
690%
Step-by-step explanation:
To find the percent increase, take the new amount and subtract the original amount
5600000-80000=5520000
Divide it by the original amount
5520000/800000
6.9
Multiply this by 100% to change from decimal form to percent form
6.9*100%
690%
