Answer:
c. (Multiply 4 by the difference of 10 and 3, then add 5)
Answer:10 over 13 x
Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2
to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13
factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)
for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x
solution: 800-10 over 13x so your answer would still be
Answer: As GH moves, the reflected image changes its position with respect to the position of the line. The polygons will touch one another if the line of reflection touches polygon ABCD.
Perpendicular lines will have negative reciprocal slopes. What that means is if u have a slope of 1/2, to find the negative reciprocal, flip the slope and change the sign.......flip 2/1, change the sign -2/1 or just -2. So the negative reciprocal for the slope of 1/2 is -2.
A. y = 1/5x + 3.....slope here is 1/5, so for a perpendicular line, u r gonna need an equation with the slope of -5.....and that would be : y + 3 = -5(x + 2).
B. Parallel lines will have the same slope. y = 5x - 2...the slope here is 5...so a parallel line will have a slope of 5.
y = mx + b
slope(m) = 5
(8,-2)...x = 8 and y = -2
now we sub, we r looking for b, the y intercept
-2 = 5(8) + b
-2 = 40 + b
-2 - 40 = b
-42 = b
so ur parallel equation is : y = 5x -42
To get your answer, you would divide your distance by your speed. You should be going about 1.4 miles per hour.
