Answer:C
Step-by-step explanation:
24/6=4
P6R2/ P2Q2R6
Cancel you have P4 left on top
Cancel you have R4 left on bottom
Q2 stays at bottom
Answer: (5,-1)
Step-by-step explanation:
Answer:
![\left[\begin{array}{ccc}(-p)&--->&q\\f&t&t\\f&t&t\\t&t&f\\t&f&f\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-p%29%26---%3E%26q%5C%5Cf%26t%26t%5C%5Cf%26t%26t%5C%5Ct%26t%26f%5C%5Ct%26f%26f%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
First, we find all the possibilities for p and q in a table:
p q
t t
t f
f t
f f
then -p:
-p q
f t
f f
t t
t f
and we apply the operator --> (rightarrow), that is only f (false) y if the first one is t (true) and the second one is f (false)
-p ---> q
f t t
f t f
t t t
t f f
So hmm check the picture below
the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)
thus