Do multiplication first.
12*96
Then do -123+ (12*196)
Finally:
12 + (the number you received from the previous question)
The dimensions of Q are 5L and 5w.
The Area outside of P = AreaQ - AreaP
Area = length*width
The Area outside of P = (5w)(5L) - wL
= 25wL - wL
= 24 wL
Solution:
According to the problem, the laptop costs $450 less than the desktop. Let x the cost of the laptop, then we get the following equation:

now, the total finance charge of $409 is from 9% of the cost of the laptop and 6.5% of the cost of the desktop. According to this, we get the following equation:

Applying the distributive property, we get:

now, placing like terms on each side of the equation, we get:

this is equivalent to:

solving for x, we get:

this means that:
The cost of the laptop is x = 2450
and
The cost of the desktop is x+450 = 2450 +450 = 2900.
So that, we can conclude that the correct answer is:
Cost of the laptop = 2450
Cost of the desktop =2900.
Answer:
1. UW // TX
2. VX // UY
3. UW ≅ TY ≅ YX
4. YW =
TV
5. TX = 2 UW
6. ∠TXV ≅∠WUY
Step-by-step explanation:
The line segment joining the midpoint of two sides of a triangle is parallel to the third side and equal to half its length
In Δ XVT
∵ U is the midpoint of VT
∵ W is the midpoint of VX
∵ XT is the 3rd side of the triangle
→ By using the rule above
∴ UW // TX ⇒ (1)
∴ UW =
TX
→ Multiply both sides by 2
∴ 2 UW = TX
∴ TX = 2 UW ⇒ (5)
∵ Y is the midpoint of TX
∴ TY = YX =
TX
∵ UW =
TX
∴ UW ≅ TY ≅ YX ⇒ (3)
∵ U is the midpoint of VT
∵ Y is the midpoint of XT
∵ VX is the 3rd side of the triangle
→ By using the rule above
∴ UY // VX
∴ VX // UY ⇒ (2)
∴ UY =
VX
∵ W is the midpoint of VX
∵ Y is the midpoint of XT
∵ TV is the 3rd side of the triangle
→ By using the rule above
∴ YW // TV
∴ YW =
TV ⇒ (4)
∵ 2 Δs UYW and XVT
∵ UY =
XV
∵ YW =
VT
∵ WU =
TX
∴
=
=
= 
→ By using the SSS postulate of similarity
∴ ∠TXV ≅∠WUY ⇒ (6)
Answer:
Ok, we know that the width of the door is 4.20m.
Then, if the arc is at the top of the door, we will have that the diameter of that "half circle" will be equal to the width of the door.
Then the diameter of the arc is 4.20m
And the radius is defined as half of the diameter, so we have:
radius = 4.20m/2 = 2.10m
And we can write this in cm (because the probelm ask for it)
1m = 100cm
then 2.10m = 2.1*100cm = 210cm
Now, we know that the perimeter of a circle is:
P = 2*pi*r
where pi = 3.14
Then the perimeter (or arc) of half a circle will be half of that:
Arc = (2*pi*r)/2 = pi*r
and r = 210cm, pi = 3.14
Arc = 3.14*210cm = 659.4cm