What is 5 1/2 of 24

WHATS THE ANSWER?? answer ASAP NO FILE AT ALL

Galina-37 [17]

Answer:

A

Step-by-step explanation:

If you flip the picture over and look at it while it is upside-down, you can see that image A is the same shape.

4 0

3 years ago

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There are 3.9 milligrams of calcium in a 1/2 ounce of cooked chicken. how many milligrams are in 6 ounces

kondor19780726 [428]

First....6÷1/2= 12
so.....12*3.9=46.8 milligram

8 0

4 years ago

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Find the center and radius of the circle defined by the equation x^2+y^2-7x+3y-4=0

scoray [572]

Answer:

C. center: (7/2, -3/2); radius: sqrt(74)/2

Step-by-step explanation:

x^2 + y^2 - 7x + 3y - 4 = 0

We can put the equation in standard form by completing the square in x and in y.

x^2 - 7x + ___ + y^2 + 3y + ___ = 4 + ___ + ___

x^2 - 7x + (7/2)^2 + y^2 + 3y + (3/2)^2 = 4 + (7/2)^2 + (3/2)^2

(x - 7/2)^2 + (y + 3/2)^2 = 16/4 + 49/4 + 9/4

(x - 7/2)^2 + (y + 3/2)^2 = 74/4

(x - 7/2)^2 + (y + 3/2)^2 = (sqrt(74)/2)^2

Answer: center: (7/2, -3/2); radius: sqrt(74)/2

3 0

3 years ago

If line segment RU is considered the base of parallelogram RSTU, what is the corresponding height of the parallelogram?

klasskru [66]

Given that line segment RU with vertices R(1, 1) and U(4, 5) is considered the base of parallelogram RSTU.

Then, the line segment ST with vertices S(7, 0) and T(10, 4) is the top of the parallelogram.

The corresponding height of the parallelogram is the length of a line with endponts at RU and ST and perpendicular to both RU and ST.

The equation of the line segment RU is given by
$\frac{y-1}{x-1} = \frac{5-1}{4-1} = \frac{4}{3} \\ \\ 3(y-1)=4(x-1) \\ \\ 3y-3=4x-4 \\ \\ 3y=4x-1 \\ \\ y= \frac{4}{3} x- \frac{1}{3}$

Recall that given that two lines are perpendicular, the product of the slope of the two lines is -1.
Let the slope of the line perpendicular to line RU be m, then
$\frac{4}{3} m=-1 \\ \\ m=- \frac{3}{4}$

Thus, the equation of the line perpendicular to RU passing through point (1, 1) is given by
$y-1=- \frac{3}{4} (x-1) \\ \\ 4(y-1)=-3(x-1) \\ \\ 4y-4=-3x+3 \\ \\ 4y=-3x+7 \\ \\ y=- \frac{3}{4} x+ \frac{7}{4}$

The equation of the line segment ST is given by
$\frac{y-0}{x-7} = \frac{4-0}{10-7} = \frac{4}{3} \\ \\ 3y=4(x-7)=4x-28 \\ \\ y= \frac{4}{3} x- \frac{28}{3}$

The line perpendicular to line segment RU intersected line segment ST at the point given by
$- \frac{3}{4} x+ \frac{7}{4}=\frac{4}{3} x- \frac{28}{3} \\ \\ \frac{4}{3} x+\frac{3}{4} x=\frac{7}{4}+\frac{28}{3} \\ \\ \frac{25}{12} x= \frac{133}{12} \\ \\ x= \frac{133}{25} \\ \\ y=\frac{4}{3} \left(\frac{133}{25}\right)- \frac{28}{3}= -\frac{56}{25}$

Thus, the corresponding height of the parallelogram is the line with endpoints
$(1,1) \ and \ \left(\frac{133}{25},-\frac{56}{25}\right)$

Recall that the length of a line passing through points
$(x_1,y_1) \ and \ (x_2,y_2)$
is given by
$l= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Thus, the length of the line passing through points
$(1,1) \ and \ \left(\frac{133}{25},-\frac{56}{25}\right)$
is given by
$l= \sqrt{\left(\frac{133}{25}-1\right)^2+\left(-\frac{56}{25}-1\right)^2} \\ \\ = \sqrt{\left( \frac{108}{25}\right)^2+\left(- \frac{81}{25} \right)^2}= \sqrt{ \frac{11,664}{625} + \frac{6,561}{625} } \\ \\ = \sqrt{ \frac{729}{25} } = \frac{27}{5} =5.4$

Therefore, <span>the corresponding height of the given parallelogram is 5.4 units</span>

8 0

4 years ago

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17. Ms. Harper drove her car 115 miles on 5

eduard

Set it up as a proportion

115/5=n/15
And then you cross multiply
5•n=15•115
5n=1725
n=345 miles

8 0

3 years ago

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