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kramer
3 years ago
11

What is the perimeter of the rectangle?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

Answer:

10 in.

Step-by-step explanation:

<u>GIVEN :-</u>

  • Length = 3 in.
  • Width = 2 in.

<u>TO FIND :-</u>

  • Perimeter of rectangle

<u>SOLUTION :-</u>

Using the formula \boxed{Perimeter = 2(Length + Width)} ,

Perimeter of the rectangle given in question = 2(3 + 2) = 10 in.

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➷ All sides are equal in length in a rhombus

Therefore:

3x - 1 = x + 5

Subtract x from both sides and add 1 to both sides

2x = 6

Divide both sides by 2:

x = 3

(3) + 5 = 8

IN = 8 (whatever the unit is)

➶ Hope This Helps You!

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4 years ago
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If second and third hypotheses were formulated for the relationship between temperature and the pressure of a gas and are tested
Elis [28]

Answer:

working hypothesis.

Step-by-step explanation:

Hypothesis is a technique in mathematics used to identify between two events. The event is tested for hypothesis using the null hypothesis and an alternative hypothesis is set to compare the results. If there are more than one hypothesis then there is working hypothesis technique used to identify the conclusion.

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3 years ago
Can someone help me with this question?
KonstantinChe [14]
-3. Put the two equation equal to each other and solve. 
4x+18=2x+12
-2x=-2x 
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What is a domain and range <br>and how do I find it ​
Mademuasel [1]

Answer: Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

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A right triangle is inscribed in a circle as shown. What is the area of the shaded region. Diameter of 12 and 9 cm in triangle
Ksivusya [100]

Answer:

36\pi -18\sqrt{7}

Step-by-step explanation:

Every inscribed right triangle has its hypotenuse as the same size of the Diameter. Assuming that, this is the case check the picture below.

So the hypotenuse= D=2R=12

  1. Shaded Area = Area of the Circle- Area of the Triangle
  • Area of Circle:

A_{circle}=\pi (6)^{2}=36\pi

  • Area of the Triangle:

Finding the Triangle base via the Pythagorean Theorem

a^2=b^2+c^2\\12^2=9^2+c^2\\144-81=c^2\\c=\sqrt{63}\\c=3\sqrt{7}\approx 7.94

Now plugging in the base of the triangle on that formula:

A=\frac{bh}{2}\\A=\frac{3\sqrt{7}*12}{2}\\A=18\sqrt{7}

Finally,

Shaded Area = 36\pi -18\sqrt{7} cm^{2} \approx 65.48 cm^{2}

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