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3 years ago

Solve the equationx+4=5x+2

Mathematics

2 answers:

Vaselesa [24]3 years ago

4 0

Answer:

1/2 or 0.500

Step-by-step explanation:

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

-4x + 2 = -2 • (2x - 1)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : -2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : 2x-1 = 0

Add 1 to both sides of the equation :

2x = 1

Divide both sides of the equation by 2:

x = 1/2 = 0.500

One solution was found :

x = 1/2 = 0.500

Olin [163]3 years ago

3 0

x+4=5x+2

4=4x+2

2=4x

x=0.5

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Read 2 more answers

If the confidence level is 90%, find the Margin of sampling error. The population is normally distributed, the sample size is 15

charle [14.2K]

Answer:

$ME = 1.761* \frac{5}{\sqrt{15}}=2.273$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X= 75$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=15 represent the sample size

Solution to the problem

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,14)".And we see that $t_{\alpha/2}=1.761$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$

And if we replace the values we got:

$ME = 1.761* \frac{5}{\sqrt{15}}=2.273$

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3 years ago