Answer:
x = ±
Step-by-step explanation:
Given
x² - 7x + 9 = 0 ( subtract 9 from both sides )
x² - 7x = - 9
Solve using the method of completing the square
add ( half the coefficient of the x- term)² to both sides
x² + 2( - )x +
= - 9 +
(x - )² =
( take the square root of both sides )
x - = ±
= ±
( add
x = ±
=
The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
<h3>What is the value of sin (π/2)?</h3>The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.
Suppose the value of this function is <em>x</em>. Thus,
Solve it further,
......1
The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,
Put this value in the equation 1,
Thus, the range will be,
Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
Learn more about the sine values here;