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LenaWriter [7]
2 years ago
15

A circle has an area of 2290.221. What is the radius? (round to the nearest whole number)

Mathematics
1 answer:
erica [24]2 years ago
8 0

Answer: 27

Step-by-step explanation:

use the formula for the area of circle and solve for r: A=pi r^2

2290.221=pir^2 <---divide by pi

729=r^2 <--- square root both sides

27=r

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hello! 20 points for this one answered correctly and explained! question: which pair of numbers with sum 8 has the largest produ
Andre45 [30]
4&4 b/c 4+4=8 & 4x4=16
8 0
3 years ago
ONLY NEED PART B HELP
bezimeni [28]

Answer: 48 model cars

Step-by-step explanation: 1. You know that the ratio of the number of model cars that Jim owns to the number of model cars Terrence owns is 4:3.

2. Let's call the number of model cars that Jim owns is , therefore, you can solve the exercise as following:

3. Therefore, Jims owns 48 model cars.

4 0
2 years ago
Express 0.361 recurring as a fraction.<br> (only the 61 recurs)
Oduvanchick [21]

9514 1404 393

Answer:

  179/495

Step-by-step explanation:

When the repeating decimal starts at the decimal point, the repeating digits can be turned into a fraction by putting them over the same number of 9s. That is, 0.61616161... is equivalent to 61/99.

Here, the repeating part is 1/10 that value, so is 61/990. This is added to the non-repeating part, which is 0.3 = 3/10.

Then the entire decimal is ...

  0.361_61 = 3/10 + 61/990 = (297 +61)/990 = 358/990 = 179/495

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
A colleague has been tutoring six students in 11th grade to prepare for the ACT. This colleague has asked you to evaluate the pe
marissa [1.9K]

We have been given that a colleague has been tutoring six students in 11th grade to prepare for the ACT. Student scores were as follows: 20, 18, 16, 15, 23, 20. We are asked to find the mean of the ACT scores.

We will use mean formula to solve our given problem.  

\text{Mean}=\frac{\text{Sum of terms}}{\text{Number of terms}}

\text{Mean}=\frac{20+18+16+15+23+20}{6}

\text{Mean}=\frac{112}{6}

\text{Mean}=18.66666

Upon rounding to nearest whole number, we will get:

\text{Mean}\approx 19

Therefore, the mean of the ACT scores is 19 and option 'c' is the correct choice.

5 0
3 years ago
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