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Nataly [62]
3 years ago
13

The linear function A(t)= 55t + 120 represents the amount, A, in Normans saving account where T represents time in weeks since h

e has been saving money for vacation what does a slope by 55 represent in the context of this scenario.
A. Norman will have saved enough to go on vacation after 55 weeks
B. Norman has been putting money into his savings account for five weeks
C. Norman has been deposing $55 each week into his savings account
D. Norman had $55 in his savings account before he started saving for a vacation
Mathematics
1 answer:
Anton [14]3 years ago
7 0

Answer:

C

Step-by-step explanation:

The reason it is C because if the answer was A, then the 55 would have to have been the T since the T represents time in weeks. If it was B, look at explanation for A. It is basically the same reason why. It is not D because if he already the 55 dollars in his savings then the 55 would have been the B of the equation which right now is 120. By process of elimination, your answer should be C. Also the fact that Norman was depositing 55 dollars EACH week is a big help.

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Answer:

21 + 4  = 25

Step-by-step explanation:

this is the answer because the temperature fell 4 degrees in the last hour.

so we have to add back that 4 to get the answer.

our equation will be 21 + 4 equals 25.

hope this helps!

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The graph for the equation y=-2x+1 is shown below.
Tpy6a [65]

Answer:

Step-by-step explanation:

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3 years ago
James rode k kilometers on his bike this week. Express the number of kilometers that Ivan rode on his bike in terms of k if he r
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Step-by-step explanation:

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1/2 + 5/3 - 1<br>------------------<br> 3/4
Sav [38]
Hey there :)

\frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} }
      ↓ Is the same as
\frac{1}{2} + \frac{5}{3} -1 ÷ \frac{3}{4}

Since it is a division by fraction, we can multiply by what is called the reciprocal
( The attached picture might help you )
( \frac{1}{2} + \frac{5}{3} - 1 ) × \frac{4}{3} 
     ↓ For this part, we need the common denominator, which is 6
\frac{1(3)}{2(3)}+ \frac{5(2)}{32)}  \frac{1(6)}{1(6)} × \frac{4}{3}

\frac{3}{6}+ \frac{10}{6}  - \frac{6}{6} × \frac{4}{3}
\frac{7}{6} × \frac{4}{3}
\frac{14}{9} =  1\frac{5}{9}
  ↑
Your final answer
 

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A puppy weighed 2kg.
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Answer:

3.5 - 2  \times 100 \div 2

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