What is the locus of all points in the plane equidistant from two given lines in the plane?

1 answer:

5 0

It will be a line passing in a direction between the 2 lines. Either parallel to them ( if they are also parallel) or at an angle which bisects the angle between the 2 lines.

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Solve the system by the method of your choice x=3y-6,2x-6y=-12

igor_vitrenko [27]

The "system" of equations can't be solved for (x, y), because there's no "system" of equations given. There's really only one equation.

Either of these two equations can be massaged to look exactly like the other one. And if you graph both equations, you find that they're both the same line on the graph.

ANY point on the line is a solution to both equations ... and we all know how many different points there are on a line.

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ladessa [460]

3 beach 2 skiing and 2 camp

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URGENT!!!!!!!! 40 POINTS AND BRAINLIEST!!!!!!!!

gayaneshka [121]

Answer:

its c because parallel lines are lines that are always the same distance apart all of these are the same distance apart

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Determine the solution to the system of equations by using substitution. <br> Y=4x+10<br> Y=-5x-10

amm1812

Steps:
1. Substitute the y in 4x + 10 with -5x-10
-5x-10= 4x + 10
2. Add 5x on both sides
-10= 9x + 10
3. Subtract 10 on both sides
-20= 9x
4. Divide by 9 on both sides
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A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla

Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

$\frac{4}{12} * \frac{8}{11} = \frac{32}{132}$ or 0.2424 or 24.24%

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3 years ago