Answer:
a. x/y = 2 b) y/x +y =1/3 c) x-y/y= 1 d) y/x = 1/2
Step-by-step explanation:
Solve for
a) x/y
as we know x +y/y = 3
x+y= 3y
x= 3y-y
x= y(3-1)
x/y= 3-1
x/y = 2
b) y/x+y
as we know x +y/y = 3
x+y = 3y
1= 3y/x+y
1/3 = y/x+y
So y/x +y =1/3
C) x-y /y
as we know x +y/y = 3
x +y = 3y
subtracting 2y from both sides
x +y -2y = 3y- 2y
x-y = y
dividing both sides by y
x-y/y = y/y
x-y/y= 1
d) y/x
as we know x +y/y = 3
x +y = 3y
x= 3y- y
x= 2y
dividing both sides by x
x/x = 2y/2x
1 = 2 x (y/x)
1 / 2 = y/x
Or y/x = 1/2
Best of luck.
please mark me brainliest.
<h3>
Answer:</h3>
∠C = 40°
∠D = 75°
<h3>
Step-by-step explanation:</h3>
AB ║ CD, so AD and BC are transversals. The angle pairs (A, D) and (B, C) are "alternate interior angles", hence congruent.
∠C = ∠B = 40°
∠D = ∠A = 75°
<h3>
Answer: Choice C, 2/3</h3>
============================================
Work Shown:
A = # of candies that are not green
A = (# of red)+(# of yellow)+(# of blue)
A = 25+15+20
A = 60
B = # of candies total
B = (# of red)+(# of green)+(# of yellow)+(# of blue)
B = 25+30+15+20
B = 90
P(not green) = probability of selecting candy that is not green
P(not green) = (# of candies not green)/(# of candies total)
P(not green) = A/B
P(not green) = 60/90
P(not green) = (2*30)/(3*30)
P(not green) = 2/3
Point, slope, y-intercept, never, no, slope, y-intercept, same, infinite, negative coefficits, 90 degree, one, elimination, substitution, <, >, greater than or equal to sign, less than or equal to sign, greater than, less than, always, shaded area.
Hope this helps!!
當我點擊圖片查看答案時，一切都很模糊，我什麼也看不到。拍個更清晰的圖讓我回答一下！！
