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Likurg_2 [28]
3 years ago
12

Find sinx given cos2x=5/9

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

sinx = √2/3

Step-by-step explanation:

cos2x = 1-2sin²x

5/9 = 1-2sin²x

2sin²x =1-5/9

2sin²x = 4/9

sin²x = (4/9)/2

sin²x = (4/9)*(1/2)

sin²x = 2/9

sinx = √2/3

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Answer:

Given Polynomial:

80b^4-32b^2c^3+48b^4c

Factors of Coefficient of terms

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Common factor of the coefficient of all term is 16.

Each term contain variable. So the Minimum power of b is common from all terms.

Common from all variable part comes b².

So, Common factor of the polynomial = 16b²

⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )

⇒ 16b² ( 5b² - 2c³ + 3b²c )

Therefore, Statements that are true about David's word are:

The GCF of the coefficients is correct.

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In step 6, David applied the distributive property

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3 years ago
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