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jeka57 [31]
3 years ago
5

What is bigger 4/5 or 5/9

Mathematics
2 answers:
diamong [38]3 years ago
7 0
4/5

It is 0.8

5/9
is 0.555....
Nina [5.8K]3 years ago
7 0
Work: 4/5 or 5/9
Find common denominator
Common denominator is 45
4/5×9/9= 36/45
5/9×5/5=25/45
36/45 is bigger than 25/45
Answer: 4/5
Check your work:
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What is the volume of a hemisphere with a diameter of 7.7 ft, rounded to the nearest tenth of a cubic foot?
Nady [450]

Answer: 119.57 cu. ft.

Step-by-step explanation:

Volume of a hemisphere = (2/3)πr^3

= (2/3) * 22/7 * 3.85^3

6 0
3 years ago
Common factor of 12/15
Evgesh-ka [11]
The gcf of 12/15 is 3 (simplest terms is 4/5)
8 0
3 years ago
Craig’s June water bill listed two meter reading. The previous reading was 6,372 ccf and the present reading is 6501 CFC. How mu
romanna [79]

Answer: Craig's household use of water during the billing period = 129 CFC

Explanation:

Since we have given that

Craig's June water meter's previous reading =6372 CFC

Craig's water meter's present reading =6501 CFC

Craig's household use during the billing period =6501 -6372= 129 CFC

So, we get that

Craig's household use of water during the billing period = 129 CFC


8 0
3 years ago
Pls help cause idk how to do this?!!?
tatiyna
U first start of with writing the numbers from small to greatest so it will be 45,53,53,54,60,62,63,67,68 after that your min will be your smallest, 45 and your Max is 68 than for you mid you start off at both ends with your finger ( if needed) to get your middle which in this case, it’s 60. Now for your Q1 u do the exact same thing for mid but instead of you start from 45 to 60 which gets u to 53 as ur Q1. Finally for your Q3 you you starting off at 60 and ending at 68 and doing the same thing again ur Q3 will be 63.
4 0
3 years ago
En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
2 years ago
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