All categories

3 years ago

In a axiomatic system which category do pionts and lines and plane belong to?

Mathematics

2 answers:

hoa [83]3 years ago

8 0

Answer:

Undefined terms basicly was he said

Step-by-step explanation:

Grace [21]3 years ago

6 0

In an axiomatic system, points, lines, and planes belong to the category of undefined terms

You might be interested in

Which problem is solved using this model? 15÷15 3÷115 3÷15 15÷15 https://static.k12.com/nextgen_media/assets/1503272-MAT

Pie

Answer:

As the model is shown below.

As per model a thing is divided into five parts.There are three things and each one of them is being divided into five equal parts.

The value of fifth part of each of them is 1/5.

If we consider each part of a thing as one,

So, total number of parts = 15

Total thing=3

So, the answer of the above model is 3÷ 15.

Out of all the options which are 15÷15 , 3÷115 , 3÷15, 15÷15 →3÷15 is correct.

5 0

2 years ago

What is the solution to the system graphed below?

Feliz [49]

Answer:

Option D.

Step-by-step explanation:

We need to find the solution to the system graphed below.

If a system of equation have 2 linear equation then the intersection point of both lines lines is the solution of the system of equations.

In the given graph two straight lines intersect each other at (-1,-1).

Point of intersection = (-1,-1)

So, by using the given graph we can conclude that the solution of given system of equations is (-1,-1).

Therefore, the correct option is D.

8 0

2 years ago

Read 2 more answers

The sum of 5 consecutive integers is 265. What is the fifth number in this sequence ?

Yanka [14]

Hello,
Let's assume n,n+1,n+2,n+3,n+4 the 5 numbers

n+(n+1)+...+(n+4)=5n+10=265
5n=265-10
5n=255
n=51
The 5th number is 51+4=55

6 0

3 years ago

Segments AB, EF, and CD intersect at point C, and angle ACD is a right angle. Find the value of g. Please help me

iogann1982 [59]

Answer:

37 degree

Step-by-step explanation:

AB = 180 it is a straight line

ACD = 90 degree

DE+ DCB are complimentary angles they add up to 90 they dont need to be next to each other.

DE = 53 deg

DCB = 90-53= 37 degree

g = 37 and F is its vertical angle as they share the same corner point and lay opposite each other and each have same angle 37 degree.

8 0

2 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

6 0

3 years ago