One number be x
x+(x+1)+(x+2)=63
x+x+1+x+2=63
3x+3=63
3x=63-3
3x=60
x=60:3
x=20
smallest number = x=20
middle <span>number = x+1= 20+1=21
</span>largest<span><span><span> number = x+2</span> =20+2= 22</span>
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That parts are equal to each other.
Hi there!
Let the first number be represented by X.
The second number (which is 2 more than four times the other), can be represented by 4X + 2.
We can now find the sum of this expression.
X + 4X + 2
Collect terms
5X + 2
The sum of the numbers is 18. Therefore we can set up the following equation.
5X + 2 = 18
Subtract 2.
5X = 16
Divide both sides by 5.
X = 16/5 = 3 1/5.
Therefore, the first number is 3 1/5. To find the second number we must plug in X = 3 1/5 into the expression 4X + 2
4 * (3 1/5) + 2 = 12 4/5 + 2 = 14 4/5
The two numbers are

~ Hope this helps you!
Answer: b is the answer
Step-by-step explanation: have a nice day
Answer:
3/2 x-5
Step-by-step explanation: