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sweet-ann [11.9K]

2 years ago

9

Please help and don't answer just for points and please don't get anything wrong bless your heart and ill give you points, brain

liest, and more but please solve corecttly

1 answer:

Rashid [163]2 years ago

6 0

1. 39
2. 59
3. 19
4. 162
I hope this helps :)

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Vinil7 [7]

Let's use the quadratic formula
$\frac{ - b( + - ) \sqrt{ {b}^{2} - 4ac} }{4a}$
a = 1, b = 0, c = -18
$\frac{ - (0)( + - ) \sqrt{ {(0)}^{2} - 4(1)( - 18)} } {4(1)} \\ \frac{( + - ) \sqrt{72} }{4}$
This is now split into two equations:
$\frac{ + \sqrt{72} }{4}$
and
$\frac{ - \sqrt{72} }{4}$
Since $\frac{ \sqrt{72} }{4} \\ = \frac{6 \sqrt{2} }{4} \\ = \frac{3 \sqrt{2} }{2}$
The answer is
$\frac{3 \sqrt{2} }{2} \: and \: \frac{ - 3 \sqrt{2} }{2}$
which means there are 2 real number solutions to the problem: answer B.

6 0

3 years ago

Josh had $12.80 to spend for lunch. For lunch, he purchased two hamburgers that cost $2.75 each, cheese fries that cost $1.85, a

GREYUIT [131]

He had $3.27 left 2.75x2)+1.85+2.18+9.53 12.80-9.53=3.27 left

4 0

2 years ago

Question 11 (5 points)

KATRIN_1 [288]

Answer:

Yes

Step-by-step explanation:

Substitute the x value in the ordered pair for the x in the equation, or 2, and the y-value (6) in for y. So, 2 + 6 = 8, and this is true. Then do 3(2) - 6 = 0, which is also true.

6 0

2 years ago

Given that tan theta = -4/7, and 270° < theta < 360°, what is the exact value of sec theta

aleksley [76]

Answer:

sec Θ = $\frac{\sqrt{65} }{7}$

Step-by-step explanation:

Using the trigonometric identity

sec²Θ = tan²Θ + 1

Since 270° < Θ < 360° ← that is fourth quadrant, then

sec Θ > 0, thus

sec²Θ = (- $\frac{4}{7}$ )² + 1 = $\frac{16}{49}$ + 1 = $\frac{65}{49}$ , then

sec Θ = $\sqrt{\frac{65}{49} }$ = $\frac{\sqrt{65} }{7}$

6 0

2 years ago

Supposed five plain hamburgers cost the same as three super burgers. Also suppose that one super burger cost $.30 more than one

noname [10]

Answer:

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

Step-by-step explanation:

We have three conditions

(1) 5P = 3S

(2) S = C + 0.30

(3) P = C – 0.20 Substitute (3) into (1)

=====

(4) 5(C – 0.20) = 3S Substitute (2) into (4)

5(C – 0.20) = 3(C + 0.30) Remove parentheses

5C – 1.00 = 3C + 0.90 Add 1.00 to each side

5C = 3C + 1.90 Subtract 3C from each side

2C = 1.90 Divide each side by 2

C = $0.95 Substitute C into Equation (2)

=====

S = 0.95 + 0.30

S = $1.25 Substitute C into Equation (3)

=====

P = 0.95 – 0.20

P = $0.75

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

3 0

3 years ago