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evablogger [386]
2 years ago
15

Write an equation of the line passing through point p(-2,6) that is parallel to the line x=-5

Mathematics
1 answer:
padilas [110]2 years ago
5 0

Answer:

The graph of the line x = -2  is also attached below.

Step-by-step explanation:

Given the line

x=-5

x=-5 represents the vertical. We know that the slope of a vertical line is undefined. Thus, the slope of x=-5 is undefined.

Since parallel lines have the same slopes, it means the line which is supposed to be the parallel line to the given line and passing through p(-2, 6) must also be in the form (x = a).

As the line passes through (-2, 6). As the line is vertical, meaning no matter what the value of y is, the x-value remains the same.

Thus, the equation of the line would be x = -2

The graph of the line x = -2  is also attached below.

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Answer:

Center =  \boxed{1}, \: \boxed{ - 2} \: ; \: Radius =  \boxed{3}

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  - 2x + 4y - 4 = 0 \\  \\  ({x}^{2}  - 2x + 1 - 1) + ( {y}^{2}  + 4y + 4 - 4) - 4 = 0 \\  \\ ( {x}^{2}  - 2x + 1) + ( {y}^{2}  + 4y + 4) - 9 = 0 \\  \\  {(x - 1)}^{2}  +  {(y + 2)}^{2}  = 9 \\  \\ {(x - 1)}^{2}  +  {(y + 2)}^{2}  =  {3}^{2}  \\  \\ equating \: it \: with \\  \\  {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}  \\  \\ h = 1 \\ k =  - 2 \\ r = 3 \\  \\ center =  \boxed{1} \: \boxed{ - 2} \:  \: radius =  \boxed{3}

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