Given:
FG=5x+2
GH=3x-1
FG=9
Let us draw the line segment as follows,
Equating the length of FG, we get,

Substitute the value of x in the given value of GH,

And the total length FH is,

Hence, the lengths are,
Cross Multiply. 25 * 24 and 40 * 15
Yes, they are proportional
Answer:
Step-by-step explanation:
Recall that cos Ф = adj / hyp. If adj = 6 and hyp = 10, then by the Pythagorean Theorem, opp = 8: 6² + 8² = 10²
Then:
sin Ф = opp / hyp = 8/10 or 4/5
cos Ф is given: 6/10 or 3/5
tan Ф = opp / adj: 8/ 6 or 4/3
cot Ф = 1/sin Ф = 10/8 or 5/4
sec Ф = 1/ cosФ = 10/6 or 5/3
csc Ф = 1 / sin Ф = 10/8 or 5/4
Answer:
R=0.39789 ft
Step-by-step explanation:
For the perfectly mowed lawn, after one revolution, you want the lawnmower to be exactly one lawnmower's width closer to the pole. This implies that one lawnmower width should wrap around the circumference of the pole every revolution. So for this lawnmower we want:
2πR=2.5
⇒R=2.5/2π
R=0.39789 ft
yes it is right right right 100%