B should be the answer but I’m not that sure
We need to solve for x. Let's try problem b:

Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:

Since this is true, your answer would be:
All real numbers
------------------------------------------------------------------
Let's solve for problem c:

Let's isolate x, so subtract 1 from both sides:

Since x can't have a coefficient, divide both sides by 3:


So, only the value of 14 would make this equation true.
------------------------------------------------------------------
Let's try problem d:

Let's get our whole numbers on the right side. Add 1 to both sides:

Subtract 4x from the right side on both sides:

Since this is not true, your answer would be:
No solution
。ₓ ू ₒ ु ˚ Your answer would be 12.75! ˚ ू ₒ ु ₓ。
⭒❃.✮:▹ Considering 15% of 14.99 is 2.24, we would need to subtract that amount from 14.99.
14.99 - 2.24 = 12.75. ◃:✮.❃⭒
Hope this helps! ♡
6 sin 2x = 6 cos x Using the identity sin 2x = 2 sin x cos x:-
12 sin x cos x = 6 cos x
6 cos x ( 2 sin x - 1) = 0
either 6 cos x = 0 or 2 sin x - 1 = 0 so sin x = 1/2
x = pi/2, 3pi/2 , pi/6, 5pi / 6
answer is ( pi/6, pi/2, 5pi/6, 2pi/2)