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3 years ago

Multiply (2x+1)(6x^2+8+9)

Mathematics

1 answer:

spayn [35]3 years ago

6 0

Answer:

12x3+6x2+34x+17

Step-by-step explanation:

(2x+1)(6x2+8+9)

=(2x+1)(6x2+8+9)

=(2x)(6x2)+(2x)(8)+(2x)(9)+(1)(6x2)+(1)(8)+(1)(9)

=12x3+16x+18x+6x2+8+9

=12x3+6x2+34x+17

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(x^2-4x)^2+7x^2-28x+12=0

Valentin [98]

Answer:

$x^4-9x^2-28x=-12$

Step-by-step explanation:

$(x^2-4x)^2+7x^2-28x+12=0$

$(x^4-16x^2)+7x^2-28x=-12$

$x^4-9x^2-28x=-12$

7 0

3 years ago

a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

$\displaystyle \frac{6}{10}$

Thus the option WN has the probability

$\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}$

Now for the second option NW. The initial probability to pick a non-white counter is

$\displaystyle \frac{6}{11}$

The probability to pick a white counter is

$\displaystyle \frac{5}{10}$

Thus the option NW has the probability

$\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}$

The total probability of event A is the sum of both

$\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}$

$\boxed{\displaystyle P(A)=\frac{6}{11}}$

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3 years ago

Which set of sides would make a right angle

nlexa [21]

Answer:

PICTURE?

Step-by-step explanation:

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3 years ago

Which of the following theorems verifies that WVU = RST?

Paladinen [302]

Answer: C. LA

Explanation:

Angle W = Angle R (given)
VU = ST (given)
Angle U = Angle T = 90 (right angle of the right triangle)

Then we can say that triangle VWU = SRT (ASA)

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3 years ago

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HACTEHA [7]

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3 years ago