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nataly862011 [7]
3 years ago
12

Consider the figure below. Abraham cut regular pentagon ABCDE into quadrilateral BEGC. Which of the following statements is true

about quadrilateral BEGC? (picture included)

Mathematics
2 answers:
Genrish500 [490]3 years ago
5 0

Let 'n' be the number of side of a regular polygon each angle are equal and sum of  each angle equal to (n-2)×180. \\∴For a regular pentagon have five equal side, n=5\\ ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108° \\ Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio \\ Therefore ∠ABE : ∠CBE = 36: 72\\∴ ∠GCB + ∠CBE = 108° +72°=180°

Taya2010 [7]3 years ago
3 0

Answer:3, 4, and 6

Step-by-step explanation: Trust me I took the test. Hope it helps

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6 0
3 years ago
∠A and ∠B are complementary angles. The measure of ∠A=4x° and the measure of ∠B=50°. Find m∠A. * i dont understand can someone h
jolli1 [7]

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3 0
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