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nataly862011 [7]
3 years ago
12

Consider the figure below. Abraham cut regular pentagon ABCDE into quadrilateral BEGC. Which of the following statements is true

about quadrilateral BEGC? (picture included)

Mathematics
2 answers:
Genrish500 [490]3 years ago
5 0

Let 'n' be the number of side of a regular polygon each angle are equal and sum of  each angle equal to (n-2)×180. \\∴For a regular pentagon have five equal side, n=5\\ ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108° \\ Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio \\ Therefore ∠ABE : ∠CBE = 36: 72\\∴ ∠GCB + ∠CBE = 108° +72°=180°

Taya2010 [7]3 years ago
3 0

Answer:3, 4, and 6

Step-by-step explanation: Trust me I took the test. Hope it helps

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Musya8 [376]

Answer:

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Step-by-step explanation:

In standard form, you have to put the term with the highest exponent first.

With finding the degree, you just look at the highest exponent and that's the degree. 4 is the highest exponent, so it is to the 4th degree.

The leading coefficient is the number attached to the highest exponent. 4 is the highest and the number attached to it is 2.

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3 0
3 years ago
What is the slope of the line containing (-2, 5) and (4, -4)?
bija089 [108]

Answer:

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8 0
2 years ago
Ramona owns a orange grove, and needs to harvest at least 2616 oranges to cover the costs of running the grove. If each tree bea
GuDViN [60]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following information :

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4 0
3 years ago
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MA_775_DIABLO [31]

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6 0
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