How much water must be added to 1 litre of 5% cordial mixture to produce a 4% cordial mixture?

NEVERMIND I GOT THE ANSWERquestion in photo, i cant do math help :(

Morgarella [4.7K]

|EG| / |FH| = |GD| /|HD|

6/8 = |GD|/14

|GD| =6*14/8 = 10.5

5 0

3 years ago

What is the integer value for 27˚F

Arturiano [62]

Answer:

The integer 27 is an odd number. The integer 27 is a Composite number. 13 is less than 27, so 27 is a deficient number.

7 0

3 years ago

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelo

Digiron [165]

Answer: $(\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .$

Step-by-step explanation:

Transformation rule for dilation:

$(x,y)\to(kx,ky)$ , where k = scale factor

Given : Scale factor = $-\dfrac13$

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

$(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)$

$(0,9)\times(0\times-\dfrac13,9\times-\dfrac13)=(0,-3)$

$(6,-3)\to(6\times-\dfrac13,\ -3\times-\dfrac13)=(-2,1)$

$(3,-3)\to (3\times-\dfrac13,\ -3\times-\dfrac13)=(-1,1)$

Hence, the coordinates of the image if the parallelogram = $(\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .$

8 0

3 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$