Answer:
cot x and sec x
Step-by-step explanation:
Given are 4 trignometric functions defined in the interval [0,\pi]
We are asked to identity the functions which can take values more than 1.
We have

have values always between -1 and 1 for any value of x
Hence sinx and cosx cannot take values greater than 1.

This value being ratio of cos to sin will become greater than 1 whenever cos >sin value.
SO this function can take values >1

This function being reciprocal of cos function always can take values outside
(-1,1)
Hence this value can be greater than 1
Answer:
c its the right answer
Step-by-step explanation: i just took it and got it right
Step-by-step explanation:
I dn't know this but just go onlibe=ne and search slope calculato r it'll give you the answer step by step
Answer:
-3x² +6x -1 = 0
Step-by-step explanation:
x2 - 2x + = 4(x2-2x +1)-3
x² - 2x = 4x²-8x +4 - 3
x²-4x²-2x+8x = 4-3
-3x² +6x = 1
-3x² +6x -1 = 0
Answer:
Breadth=x+2
Step-by-step explanation:
