the equation of the line is y = 3.
the slope of the line is 0.
the y-intercept is 3, so plug it into the slop-intercept-form equation:
y = mx + b
y = 0x + 3
y = 3
hope this helps!
1 box =1 foot so you would have to count the boxes away from her
as for my ans is C...
can you correct me if im wrongX
Answer:
10.4feet
Step-by-step explanation:
The set up wil form a right triangle
Length of the ramp is the hypotenuse
The length of the end of the ramp from the base= 10 feet (adjacent)
Angle of elevation = 15 degrees
Required
Length of the ramp
Using SOH CAH TOA
Cos theta = adj/hyp
cos 15 = 10/L
L = 10/cos15
L = 10/0.9659
L = 10.35
L ≈ 10.4 feet
Hence the length of the ramp is 10.4feet