Equation for the line perpendicular to the line -6x-7y=-6 having the same y-intercept as 8x-5y=10

1 answer:

4 0

Solving   <span>8x-5y=10 for y helps us to identify the y-intercept:

-5y = -8x + 10. Dividing both sides by -5, we get (8/5)x -2. Therefore, y = (8/5)x - 2; the y-intercept is (0,-2).

The equation  </span><span>-6x-7y=-6 can be solved for its slope in the same manner.
7y = -6x + 6; then y = (-6/7)x + 6/7. Its slope is -7/6. A line perpendicular to this line has slope equal to the negative reciprocal of -7/6,  which is 6/7.

So, using the slope-intercept form, y = mx + b becomes y = (6/7)x -2.</span>

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