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Alja [10]
2 years ago
9

Equation for the line perpendicular to the line -6x-7y=-6 having the same y-intercept as 8x-5y=10

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
4 0
Solving   <span>8x-5y=10   for y helps us to identify the y-intercept:

-5y = -8x + 10.  Dividing both sides by -5, we get (8/5)x -2.  Therefore, y = (8/5)x - 2; the y-intercept is (0,-2).

The equation  </span><span>-6x-7y=-6   can be solved for its slope in the same manner.
7y = -6x + 6;  then y = (-6/7)x + 6/7.  Its slope is -7/6.  A line perpendicular to this line has slope equal to the negative reciprocal of -7/6,  which is 6/7.

So, using the slope-intercept form, y = mx + b becomes y = (6/7)x -2.</span>
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Number is 22 round down to
alina1380 [7]

Answer:

22 rounds down to 20 if that is what you are asking

Step-by-step explanation:

You did not finish your question i dont think. 22 DOES round down to 20 though.

3 0
3 years ago
7(2x−a)−3(4x−a)−5(3x+2a)+a=0.
Luden [163]

Answer:

0

Step-by-step explanation:

5 0
3 years ago
The equation x 2y = 16 is in standard form. what is the slope of the line? â€""2 â€""1 â€""0.5 0.5
Savatey [412]

By rewriting the given line, we can see that the slope is equal to -1/2 or -0.5

<h3>How to get the slope of the given line?</h3>

Remember that a line is:

y = a*x + b

Where a is the slope and b is the y-intercept of the line, which is the point where the line intersects the y-axis.

Then, we can rewrite our equation:

x + 2y = 16

to:

2y = 16 - x

y = (16 - x)/2

y = (-1/2)*x + 8

Comparing with the general line equation, we can see that the slope is -1/2.

If you want to learn more about linaer equations:

brainly.com/question/1884491

#SPJ4

3 0
1 year ago
Solve: 1 5 x = -10 A) -50 B) -20 C) -2 D) 2
Inessa [10]

Answer:

In order to find x, you will have to use the operation of equality to isolate the x.


15x=-10

<em>Now, use the division property of equality and divide by 15 on both sides. This will cancel out the 15 on the left side of the equation and isolate the x completely.</em>

-10/15=\frac{-2}{3}

<em>Thus, this is your answer:</em>

\boxed{x=-\frac{2}{3} }

6 0
3 years ago
Solve 2x^2+x-4=0<br> X^2+_×+_=0
natima [27]

Answer:

Hopes it helps

Step-by-step explanation:

The Quadratic Polynomial is

2 x² +x -4=0

Using the Determinant method to find the roots of this equation

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0  ∧ x+1=0

x=0     ∧   x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

x=2 ∧ x=-2

As, you will put these values into the equation, you will find that these values does not satisfy both the equations.

So, there is no solution.

You can solve these two equation graphically also.

3 0
2 years ago
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