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Alja [10]
2 years ago
9

Equation for the line perpendicular to the line -6x-7y=-6 having the same y-intercept as 8x-5y=10

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
4 0
Solving   <span>8x-5y=10   for y helps us to identify the y-intercept:

-5y = -8x + 10.  Dividing both sides by -5, we get (8/5)x -2.  Therefore, y = (8/5)x - 2; the y-intercept is (0,-2).

The equation  </span><span>-6x-7y=-6   can be solved for its slope in the same manner.
7y = -6x + 6;  then y = (-6/7)x + 6/7.  Its slope is -7/6.  A line perpendicular to this line has slope equal to the negative reciprocal of -7/6,  which is 6/7.

So, using the slope-intercept form, y = mx + b becomes y = (6/7)x -2.</span>
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22,647 inches into miles
nydimaria [60]

22,647 inches to m iles will give you 0.35743371 of a mile (this is a repeated decimal since it goes on forever with different numbers.) Using a calculator, 22646.9998656 inches would give 0.35743371 miles (round the inches to the whole number and you will still get the same answer.) Into hundredths, you get 0.36, but changing to tenths would give 0.4.

Hope this helped!

Nate

7 0
2 years ago
Read 2 more answers
What is the exact value of cos 112.5°?
ikadub [295]
We have 112.5 = 225/2; cos112.5 < 0 because 90 < 112.5 < 180;
cos 112.5 = cos(225/2);
We use the trigonometric formula: cos(x/2) = - \sqrt{ \frac{1+cosx}{2} };
Then, cos(225/2) = - \sqrt{ \frac{1+cos225}{2} };
We have the formula: cos(270 - x) = -sinx (because cos(a-b) = cosacosb + sinasinb);
Then, cos225 = cos(270-45) = -sin45 = -\frac{ \sqrt{2} }{2} ;
Finally, cos112.5 = -\frac{ \sqrt{2- \sqrt{2} } }{2} ;

3 0
3 years ago
Expand the expression: -5(4-7c)​
Ronch [10]

Answer:

-20 + 35c

Step-by-step explanation:

Distribute the -5 in the equation.

5 0
3 years ago
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PLEASE HELP THANK YOU IN ADVANCE NEED TO SUBMIT SOON!! PLEASE PLEASE PLEASE HELP
Serjik [45]
Provate school in 2005
f(t)=85+18t

public school
g(t)=95+15t

graph
easy
replace g(t) and f(t) with y
y=18t+85
y=15t+95
input values for t and get values for y

y=18t+85
when t=0 y=85
when t=1 y=103
plot the oints (0,85) and (1,103)

y=15t+95
if t=0 then y=95
if t=1 then y=110
plot the points (0,95) and (1,110)

the easier way would just to be to solve the equatons but anyway
interscection point is (3 and 1/3,145)

so after 3 years (2008) it is about 145
6 0
3 years ago
A translation of trapezoid PQRS (blue) to trapezoid P'Q'R'S' (green) is shown, where the location of Q' is the origin. The coord
Kruka [31]

On USATestprep the answer is C) (c-a,-b)

8 0
3 years ago
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