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xxTIMURxx [149]
3 years ago
10

1. Find the value of the unknown angles in the following diagram.

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

z= 40

y=140

x= 115

Step-by-step explanation:

look at the pics

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Andy has a collection of movie dvds. in andys collection 3/5 of the dvds are action 1/4 of the dvds are comedy. andy said that 4
Cerrena [4.2K]

This question is based on greatest common multiple.

Answer:

Cynthia is right that Andy made an error.

Step-by-step explanation:

As per Andy, action dvds are = \frac{3}{5}

And comedy dvd's are = \frac{1}{4}

So, in total these become = \frac{3}{5}+ \frac{1}{4}

= \frac{12+5}{20} = \frac{17}{20}

This is not 4/9 as per Andy.

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3 years ago
What is the area of the figure?
AysviL [449]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Draw a solid with the following front, side, and top views.
Lapatulllka [165]
It is a rectangular pyramid
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4 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
Please helppp ;-; how do you determine the end behavior of a function?
Karolina [17]

Answer:

End Behavior of a Function. The end behavior of a polynomial function is the behavior of the graph of f( x ) as x approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

Step-by-step explanation:

3 0
2 years ago
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