The equation of the graph line is 2X-3Y=12

Mathematics

2 answers:

Finger [1]3 years ago

6 0

The answer is A.-4 that’s the answer for this question

Klio2033 [76]3 years ago

3 0

Answer:

A. -4

Step-by-step explanation:

For solving for x intercepts analytically. You can set the the y in the equation to 0. So, 2x-3(0)=12, and solving for x will get you -4.

You can also solve graphically by plugging in the equation and looking at where it intercepts the x axis.

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Which of the following is written as a rational function?

Brrunno [24]

We have to identify the rational function among the given functions.

Rational function is a function that is the ratio of two polynomials. It is rational because one polynomial is divided by the other polynomial, like a ratio.

1. Consider the first function $G(x)= -2x$ , since it is not a function that is the ratio of two polynomials. So, it is not a rational function.

2. Consider the second function $P(x)= 3x+4$ , since it is not a function that is the ratio of two polynomials. So, it is not a rational function.

3. Consider the third function $Q(x)= x^2-8x+1$ , since it is not a function that is the ratio of two polynomials. So, it is not a rational function.

4. Consider the fourth function $F(x)= \frac{x+2}{5x}$ , since it is a function that is the ratio of two polynomials (x+2) and (5x). So, it is a rational function.

So, Option D is the correct answer.

6 0

3 years ago

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Help me please i only have a small amount of time

Sveta_85 [38]

Answer: 0.83

Step-by-step explanation:

5 0

3 years ago

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In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were consi

valentina_108 [34]

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges

$=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\$

$=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329$