Answer:
(A)Cost of Rental A, C= 15h
Cost of Rental B, C=5h+50
Cost of Rental C, C=9h+20
(B)
i. Rental C
ii. Rental A
iii. Rental B
Step-by-step explanation:
Let h be the number of hours for which the barbeque will be rented.
Rental A: $15/h
Rental B: $5/h + 50
- Cost of Rental B, C=5h+50
Rental C: $9/h + 20
- Cost of Rental C, C=9h+20
The graph of the three models is attached below
(b)11.05-4.30
When you keep the barbecue from 11.05 to 4.30 when the football match ends.
Number of Hours = 4.30 -11.05 =4 hours 25 Minutes = 4.42 Hours
-
Cost of Rental A, C= 15h=15(4.42)=$66.30
- Cost of Rental B, C=5h+50 =5(4.42)+50=$72.10
- Cost of Rental C, C=9h+20=9(4.42)+20=$59.78
Rental C should be chosen as it offers the lowest cost.
(c)11.05-12.30
Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours
- Cost of Rental A, C= 15h=15(1.42)=$21.30
- Cost of Rental B, C=5h+50 =5(4.42)+50=$57.10
- Cost of Rental C, C=9h+20=9(4.42)+20=$32.78
Rental A should be chosen as it offers the lowest cost.
(d)If the barbecue is returned the next day, say after 24 hours
- Cost of Rental A, C= 15h=15(24)=$360
- Cost of Rental B, C=5h+50 =5(24)+50=$170
- Cost of Rental C, C=9h+20=9(24)+20=$236
Rental B should be chosen as it offers the lowest cost.
Answer:
convert km per hour to meter per second by multiplying 108*5/18
speed is 30m per sec
time is 20 sec so
speed is equal to distance by time
distance is equal to speed*time
so 30*20
600 meter is the answer
Answer:
13(g+4)=79=16 if -13(g+4)=79+16
g=43/13 g=-147/13=-11 1/13
Step-by-step explanation:
13g+52=95 -13g-52=95
13g=95-52 -13g=95+52
13g=43 -13g=147
g=43/13 g=-147/13=-11 1/3
Answer:
V = (1/3)pi(r^2)h (the first one)
Answer:
C
Step-by-step explanation:
Convert them all to the form y = mx + c
1)
4x + 3y = 15
3y = -4x + 15
y = -4/3 x + 5
2)
3x - 4y = -8
-4y = -3x - 8
4y = 3x + 8
y = 3/4x + 2
3)
y + 1 = 4/3(x - 6)
y + 1 = 4/3x - 8
y = 4/3x - 9
4)
y = 3/4x - 5