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3 years ago

Point A is the incenter of DEF.What is the value of n?A. 7B. 11C. 14D. 15

Mathematics

2 answers:

erica [24]3 years ago

6 0

Answer: Answer is B- 11

Step-by-step explanation: got it right on edge

ss7ja [257]3 years ago

4 0

Answer:

B.11

Step-by-step explanation:

It's 27 degrees so,

3 times 11 is 33 and 33 - 6 is 27

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4 years ago

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Veseljchak [2.6K]

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2 years ago

Read 2 more answers

Given: △ABC, AB=5 square root 2 <br><br>m∠A=45°, m∠C=30°<br><br>Find: BC and AC

hichkok12 [17]

Answer:

Part a) $BC=10\ units$

Part b) $AC=13.66\ units$

Step-by-step explanation:

step 1

Find the length side BC

Applying the law of sines

we know that

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

we have

$AB=5\sqrt{2}\ units$

$A=45^o$

$C=30^o$

substitute

$\frac{5\sqrt{2}}{sin(30^o)}=\frac{BC}{sin(45^o)}$

solve for BC

$BC=\frac{5\sqrt{2}}{sin(30^o)}(sin(45^o))$

$BC=10\ units$

step 2

Find the measure of angle B

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

$m\angle A+m\angle B+m\angle C=180^o$

substitute the given values

$45^o+m\angle B+30^o=180^o$

$75^o+m\angle B=180^o$

$m\angle B=180^o-75^o$

$m\angle B=105^o$

step 3

Find the length side AC

Applying the law of sines

we know that

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

we have

$AB=5\sqrt{2}\ units$

$A=45^o$

$B=105^o$

substitute

$\frac{5\sqrt{2}}{sin(30^o)}=\frac{AC}{sin(105^o)}$

solve for AC

$AC=\frac{5\sqrt{2}}{sin(30^o)}(sin(105^o))$

$AC=13.66\ units$

4 0

3 years ago

Point A is the incenter of DEF.What is the value of n?A. 7B. 11C. 14D. 15​

Point A is the incenter of DEF.What is the value of n?A. 7B. 11C. 14D. 15