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inna [77]
3 years ago
15

Which number has a terminating decimal expansion? А. 12 / B. 12 C. D. 11​

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

b or d

c

Step-by-step explanation:

i hope work

yon lang kaya ko

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What is the solution of 2^x = -3x + 5?​
Lunna [17]

Answer:

1

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2 years ago
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Find the slope.<br> y = -9x +4<br> m<br> [?]
faust18 [17]

Answer:

-9

Step-by-step explanation:

with the equation y=mx+b, m equals the slope and b equals the y-intercept. whatever is in the place of m is the slope. in this case, -9.

5 0
2 years ago
(the
sleet_krkn [62]

at x = 0, y = 100, y-intercept

meaning at 0 years, at the very beginning of functioning, the satellite had 100 units of power.

at y = 0, x = 10, x-intercept

meaning, at year 10, the satellite had 0 units of power, already out of power.

4 0
2 years ago
Please help me with this. Use the combination method of substitution to solve. Please show and explain work. Thanks.
Artemon [7]

Answer:

x = 25.35 (or 2129/84) and y = 4334.04 (or 121353/28)

Step-by-step explanation:

The given equations are set up and ready to go with substitution. Simply just plug in the first equation to the second equation as both are equal to y.

Step 1: Replace y in <em>y = 87x + 2129 </em>with <em>171x</em>

171x = 87x + 2129

Step 2: Subtract 87 x on both sides

84x = 2129

Step 3: Divide both sides by 84 to get x

x = 2129/84 or 25.35 (rounded)

To get y, simply plug in x into one of the 2 original equations. In this case, I will use the first equation:

y = 171 (25.35)

y = 121353/28 or 4334.04 (rounded)

You can check your work by plugging both solutions into the calculator and see if they equal each other. The values for these answers are solely based on the equations, so if you write the <em>equations </em>wrong themselves, then that means you have the values wrong as well.

6 0
3 years ago
Whats the correct answer??
Tpy6a [65]

use the midpoint formula. It's x1 + x2 / 2, y1+y2/2. When you solve you get (0, 1/2) is the midpoint. Hope this helps


8 0
3 years ago
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