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enot [183]
3 years ago
5

3 3/4+7 7/8 please help

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
6 0

Answer:

93/8

Step-by-step explanation:

3 3/4=15/4

7 7/8=63/8

15/4+63/8

lcm=8

15*2=30

4*2=8

30/8+63/8= 93/8

Artemon [7]3 years ago
3 0

Answer:

11.625

Hope this helps you!

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The final cost of a sale item is determined by multiplying the price on the tag by 75%. Which best describes the function that r
scoundrel [369]

First we try to frame the equation between the sale price and the final cost.

Let us consider, the price to be x and the final cost to be y, since the final cost is 75% of the price, we have the below equation

y = 0.75x

This is of the form of straight line equation y = mx +c where c =0 and m = 0.75

This means the function is linear since it satisfies a straight line equation.

So, we can eliminate options (3) and (4)

Now, the function is not a continuous one because the function is has definite value which is 0.75x and this make the function discrete. Hence option (2) is eliminated

Therefore we are left with option (1) which is the answer

Answer is (1) It is linear because the ratio of the change in the final cost compared to the rate of change in the price tag is constant

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3 years ago
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Hello how are you today. Question 2(×+-5)+×=×+(-6) ​
andre [41]

Answer:

x = 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Distributive Property

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2(x + -5) + x = x + (-6)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Distributive Property] Distribute 2:                                                                 2x - 10 + x = x - 6
  2. [Addition] Combine like terms (x):                                                                   3x - 10 = x - 6
  3. [Subtraction Property of Equality] Subtract <em>x</em> on both sides:                         2x - 10 = -6
  4. [Addition Property of Equality] Add 10 on both sides:                                   2x = 4
  5. [Division Property of Equality] Divide 2 on both sides:                                  x = 2
6 0
3 years ago
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How many three letter permutations can be formed from the first five letters of the alphabet?
Vsevolod [243]

Answer:

There are 60 permutations that can be formed from the first five letters of the alphabet.

Step-by-step explanation:

The number of three letter permutations that can be formed from the first five letters of the alphabet is 5P_{3}.

5P_{3} =\frac{5!}{(5-3)!}

=\frac{5!}{2!}

= 60

Hence, there are 60 permutations that can be formed from the first five letters of the alphabet.

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Which of the following is equal to the expression listed below?
Vladimir79 [104]
10+15=25, so when you add 2+3 it equals 5 and when you times 5 by 5 it equals 25.
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2 years ago
Determine if the columns of the matrix form a linearly independent set. Justify your answer. [Start 3 By 4 Matrix 1st Row 1st Co
Volgvan

Answer:

Linearly Dependent for not all scalars are null.

Step-by-step explanation:

Hi there!

1)When we have vectors like v_{1},v_{2},v_{3}, ... we call them linearly dependent if we have scalars a_{1},a_{2},a_{3},... as scalar coefficients of those vectors, and not all are null and their sum is equal to zero.

a_{1}\vec{v_{1}}+a_{2}\vec{v_{2}}+a_{3}\vec{v_{3}}+...a_{m}\vec{v_{m}}=0  

When all scalar coefficients are equal to zero, we can call them linearly independent

2)  Now let's examine the Matrix given:

\begin{bmatrix}1 &-2  &2  &3 \\ -2 & 4 & -4 &3 \\ 0&1  &-1  & 4\end{bmatrix}

So each column of this Matrix is a vector. So we can write them as:

\vec{v_{1}}=\left \langle 1,-2,1 \right \rangle,\vec{v_{2}}=\left \langle -2,4,-1 \right \rangle,\vec{v_{3}}=\left \langle 2,-4,4 \right \rangle\vec{v_{4}}=\left \langle 3,3,4 \right \rangle Or

Now let's rewrite it as a system of equations:

a_{1}\begin{bmatrix}1\\ -2\\ 0\end{bmatrix}+a_{2}\begin{bmatrix}-2\\ 4\\ 1\end{bmatrix}+a_{3}\begin{bmatrix}2\\ -4\\ -1\end{bmatrix}+a_{4}\begin{bmatrix}3\\ 3\\ 4\end{bmatrix}=\begin{bmatrix}0\\ 0\\ 0\end{bmatrix}

2.1) Since we want to try whether they are linearly independent, or dependent we'll rewrite as a Linear system so that we can find their scalar coefficients, whether all or not all are null.

Using the Gaussian Elimination Method, augmenting the matrix, then proceeding the calculations, we can see that not all scalars are equal to zero. Then it is Linearly Dependent.

 \left ( \left.\begin{matrix}1 &-2  &2  &3 \\ -2 &4  &-4  &3 \\ 0 & 1 &-1  &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )R_{1}\times2 +R_{2}\rightarrow R_{2}\left ( \left.\begin{matrix}1 &-2  &2  &3 \\ 0 &0 &9  &0\\ 0 & 1 &-1  &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\ R_{2}\Leftrightarrow  R_{3}\left ( \left.\begin{matrix}1 &-2  &2  &3 \\ 0 &1  &-1  &4 \\ 0 &0 &9  &0 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\left\{\begin{matrix}1a_{1} &-2a_{2}  &+2a_{3}  &+3a_{4}  &=0 \\  &1a_{2}  &-1a_{3} &+4a_{4}  &=0 \\  &  &  &9a_{4}  &=0 \end{matrix}\right.\Rightarrow a_{1}=0, a_{2}=a_{3},a_{4}=0

S=\begin{bmatrix}0\\ a_{3}\\ a_{3}\\ 0\end{bmatrix}

3 0
3 years ago
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