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3 years ago

Plz help me 5th grade work

Mathematics

2 answers:

anyanavicka [17]3 years ago

6 0

Answer:

8 AND 12

Step-by-step explanation:

MAURICE 8

MIRANDA 12

ira [324]3 years ago

4 0

Maurice 8

Miranda 12

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The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

Amy worked 16 hours more than Brayden last month. If Amy worked 8 hours for every 7 hours that Brayden worked, how many hours di

marishachu [46]

Answer:

Amy worked for 128 hours while Brayden worked for 112 hours

Step-by-step explanation:

Given

Let A represents Amy and B represents Brayden

A = 16 + B ------(1)

A:B = 8:7------- (2)

Required

Find A and B;

Convert (2) to fractions

$\frac{A}{B} = \frac{8}{7}$

Cross Multiply

$7 * A = 8 * B$

$7A = 8B$

Substitute A = 16 + B in the above expression

$7(16 + B) = 8B$

Open Bracket

$7 * 16 + 7 * B = 8B$

$112 + 7B = 8B$

Subtract 7B from both sides

$112 + 7B - 7B = 8B - 7B$

$112 = B$

$B = 112$

Recall that A = 16 + B

Hence, $A = 16 + 112$

$A = 128$

<em>This implies that Amy worked for 128 hours while Brayden worked for 112 hours</em>

8 0

3 years ago

Lena and Jade had a total of $36. Lena had twice as much as Jade. After each of them bought a movie ticket. Lena had 3 times as

marusya05 [52]

Lena had $24 at the beginning
the movie ticket was $6
it's just basic algebra

4 0

3 years ago

Pierce works at a tutoring center on the weekends. At the center, they have a large calculator to use for demonstration purposes

icang [17]

Answer:

504 millimeters (or 50.4 cm)

Step-by-step explanation:

Width of key in student calculator = 14 millimeter (1.4 cm)

Width of key in demonstration calculator = 2.8 cm

Thus, the demonstration calculator's dimensions are twice that of students' (in cm)

Also given, student calculator height as 252 millimeters (25.2 cm)

Thus demonstration calculator height will be twice of that = 50.4 cm (or 504 millimeters)

5 0

3 years ago

1. When you multiply an equation by a value, are you changing the solutions of that equation? Explain. 44 POINTS!!

jolli1 [7]

Answer: Yes. When you solve your equations, you're solutions will change a little bit. It's good because it'll give you the right answer.

I hope this helps you and I hope it's right. ☺

3 0

3 years ago