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vichka [17]
3 years ago
14

Robin Hood has captured three purses of money. The first purse holds two silver pieces, the second purse holds two gold pieces a

nd the third purse holds one silver piece and one gold piece. You randomly choose a purse and pull out one coin. It is a silver piece – what is the probability that the other coin in the bag is also silver?
Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
No, the probability wouldn't be 50/50 because there are 3 silver coins in all. Like the question said, there is a purse with two silver and one with one gold and one silver, so therefore it is a 1/3 chance that the other coin you pull out is a silver coin. (/^ω^)/ 
Sladkaya [172]3 years ago
4 0
50/50 is the propability
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Whats the answer for 6b+7-2b=1+5b
Alecsey [184]

Solution,6b+7-2b=1+5b\quad :\quad b=6

Steps:

6b+7-2b=1+5b

\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b

\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7

\mathrm{Simplify}, 4b=5b-6

\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b

\mathrm{Simplify}, -b=-6

\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}

\mathrm{Simplify}, b=6

\mathrm{The\:Correct\:Answer\:is\:b=6}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

3 0
3 years ago
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Help with this problem
natita [175]
Y = 6x - 4

basically, we just sub answer choices in to see which ones make the equation true.

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What's the value of<br><img src="https://tex.z-dn.net/?f=%20%3D%20%20%3E%2025%20%5Ctimes%20386%20%2B%203219%20%5Cdiv%202" id="Te
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Answer:

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Step-by-step explanation:

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7 0
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Feliz [49]

Answer:

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x= -\frac{8y}{5} +\frac{6}{5}

Step-by-step explanation:

8 0
3 years ago
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