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3 years ago

Is 3(4x-2)=12x-6 no solution,one solution,infinitely many solutions

Mathematics

2 answers:

LenaWriter [7]3 years ago

6 0

Answer:

This has no solution because if you were to try and solve it nothing would happen.

Step-by-step explanation:

kifflom [539]3 years ago

5 0

Answer:

Technically, all values of x will make this equation true. It is infinitely many solutions. Hope this helps please mark brainliest if it does!

Step-by-step explanation:

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Write the equation of a line that is perpendicular to y=7/5 x+6, that passes through the point (2,-6).

EleoNora [17]

Answer:

y = -5/7x - 4.57

Step-by-step explanation:

8 0

3 years ago

How many 1/3 inch cubes does it take to fill a box with width 2 2/3 inches, lengths 3 1/3 inches, and height 2 1/3 inches?

Nataly [62]

Answer:

560 cubes

Step-by-step explanation:

width: 8 cubes

length: 10 cubes

height: 7 cubes

volume: 8*10*7=560

divided l, w, and h by 1/3 to get them in cubes

7 0

3 years ago

Read 2 more answers

Find the midpoint of the line joining A(3,5) and B(1,3).

k0ka [10]

Answer:

<h3> $\boxed{ \boxed{ \bold{ ( \: 2 , \: 4 \: )}}}$ </h3>

Step-by-step explanation:

Given,

A ( 3 , 5 ) ⇒( x₁ , y₁ )

B ( 1 , 3 )⇒( x₂ , y₂ )

Let's find the midpoint of the line:

$\sf{ (\frac{x1 + x2}{2} \: , \frac{y1 + y2}{2}) }$

plug the values

⇒ $\sf{( \frac{3 + 1}{2} \: , \frac{5 + 3}{2} )}$

Add the numbers

⇒ $\sf{( \frac{4}{2} \: , \frac{8}{2} )}$

Calculate

⇒ $\sf{(2 \:, 4 \: )}$

Hope I helped!

Best regards!

6 0

3 years ago

PLEASE HELP<br><br> Identify the radius and center <br><br><br>x^2 +y^2 -6x -2y + 1 = 0

Trava [24]

Answer:

The center is the point (3,1) and the radius is 3 units

Step-by-step explanation:

we know that

The equation of a circle in standard form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

we have

$x^{2}+y^{2}-6x-2y+1=0$

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}-6x)+(y^{2}-2y)=-1$

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

$(x^{2}-6x+9)+(y^{2}-2y+1)=-1+9+1$

$(x^{2}-6x+9)+(y^{2}-2y+1)=9$

Rewrite as perfect squares

$(x-3)^{2}+(y-1)^{2}=9$

The center is the point (3,1) and the radius is 3 units

4 0

4 years ago

Exspression that is equivalent to 15 +80

Kipish [7]

79+16, 94+1, 95 +0

Hope this helped !

4 0

3 years ago