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Liula [17]
3 years ago
6

What’s the answer? I have to pass with my credits for high school

Mathematics
1 answer:
Alex3 years ago
8 0
-0.2 or -1/5
I would use -1/5 cause it’s a fraction
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Three baseball players are playing catch. Clayton is directly south of Shawn and directly west
seropon [69]
Use Pythagorean Theorem.
8 0
3 years ago
Pic included What is value of x? Enter your answer in the box. x =
Elza [17]

Answer:

The answer to your question is x = 10

Step-by-step explanation:

Use proportions to solve this problem

Given                  (x + 4)/8 = (2x + 1)/12

                          12(x + 4) = 8(2x + 1)

Expand

                          12x + 48 = 16x + 8

Group like terms

                           12x - 16x = - 48 + 8

Simplify

                          -4x = -40

Solve for x

                              x = -40/-4

Result

                              x = 10                  

6 0
4 years ago
Which fractions are greater than -5/12 ? Choose exactly two answers that are correct.
Elis [28]
B is the answer because when you find the common denominator. B will turn into -9/24 and -5/12 is going to be  -10/12
~JZ
5 0
4 years ago
Help quick ASAP!!!!!!!!!!!
lubasha [3.4K]
I think it would be 80
8 0
3 years ago
Read 2 more answers
Help I’ll do anything just help
Gnom [1K]

Answer:

1) {n}^{2}  - 81 \\ (n - 9)(n + 9)

2) \:  \: {a}^{2}  - 121 \\ (a - 11)(a + 11)

3) \:  \:  {n}^{2}  - 16 \\ (n - 4)(n + 4)

4)  \:  \: 9 {x}^{2}  - 144 \\  {3}^{2}  {x}^{2}  -  {12}^{2}  \\ (3x - 12)(3x + 12)

5) \: 2 {x}^{2}  - 9 \\ (2x - 3)(x + 3)

6) \:  \: 4 {w}^{2}  - 9 \\  {2}^{2}  {w}^{2}  -  {3}^{2}  \\ (2w + 3)(2w - 3)

7) \:  \: 4 {n}^{2}  - 1 \\  {2}^{2}  {n}^{2}  -  {1}^{2}  \\ (2n  + 1)(2n - 1)

8) \:  \: 1 - 16 {x}^{2}  \\  {1}^{2}  -  {4}^{2}  {x}^{2}  \\ (1 - 4x)(1  +  4x)

9) \:  \: {x}^{2}   - {y}^{2}  \\ (x - y)(x + y)

10) \:  \: 9 -  {c}^{2}  \\  {3}^{2}  -  {c}^{2}  \\ (3 - c)(3 + c)

11) \:  \:  {n}^{2} -  25 \\  {n}^{2}  -  {5}^{2}  \\ (n + 5)(n - 5)

13)49 - 4 {a}^{2}  \\  {7}^{2}  -  {2}^{2}  {a}^{2}  \\ (7 - 2a)(7 + 2a)

14) {a}^{2}  {b}^{2}  -  {c}^{4}  \\ (ab -  {c}^{2} )(ab +  {c}^{2} )

15) \:  \: 4  {x}^{2}  {y}^{2}  - 9 {z}^{2} \\  {2}^{2}   {x}^{2}  {y}^{2}  -  {3}^{2}  {z}^{2}  \\ (2xy - 3z)(2xy + 3z)

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0
3 years ago
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