Answer:
<u>There are:</u>
- 6 red balls - R
- 5 black balls - B
- Total number = 11 balls
<h3>A. Without replacement</h3>
i. <u>Two blacks </u>
ii. <u>The first is black</u>
or, alternatively
- P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>
i. <u>Two blacks </u>
- P(BB) = 5/11*5/11 = 25/121
ii. <u>The first is black</u>
or alternatively
- P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
Answer:
median
Step-by-step explanation:
Answer:
355,459.33
Step-by-step explanation:
42,655.12/12 = 3554.59
3554.59*100 = 355459.33
Answer:
x=6
Step-by-step explanation:
h(x) = -( x-2)^2 +16
We want when h(x) = 0
0 = -( x-2)^2 +16
Subtract 16 from each side
-16 = -( x-2)^2 +16-16
-16 = -( x-2)^2
Divide by -1
16= ( x-2)^2
Take the square root of each side
±sqrt(16) = sqrt(( x-2)^2 )
±4 = x-2
Add 2 to each sdie
2 ±4 = x-2+2
2+4 = x 2-4 =x
6 =x -2 =x
since time cannot be negative
x=6
Circle A -- center(2, 0), radius 8 Circle A' -- center(-1, 5), radius 3
