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sveticcg [70]
3 years ago
14

I NEED THE ANSWER ASAPPP!!! help please

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

Step-by-step explanation:

x^2 + 8^2 = 9^2

x^2 + 64 = 81

x^2 = 17

x = sqrt(17)

answer is D

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Draw the graphs of the lines below on the same grid to find the coordinates of the point of intersection. y + 5 = 2 x y = 7 − 2
Butoxors [25]

Answer:

The point of intersection is (3,1)

Step-by-step explanation:

Manipulate these equations to achieve the form of y = mx + c

1) y + 5 = 2x

Y = 2x - 5

2) y = 7 - 2x

Y = -2x + 7

Point of intersection is (3,1) on the graph attached

To check algebraically:

2x - 5 = -2x + 7

4x = 12

X = 3

Substitute to get y

Y = 2x - 5

Y = 2 x 3 - 5

Y = 1

Therefore (3,1)

5 0
2 years ago
I don’t understand this problem
Galina-37 [17]

Answer: 20

Step-by-step explanation:

a^2=b^2 - c^2. i think i could be wrong

6 0
3 years ago
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
Two decreased by a half of a number is 1/2 of the number
HACTEHA [7]
Answer:  The number is:  "2" .
_______________________________________________________
The expression is:  2 − (½)x = (½)<span>x  ;
                </span>→<span> in which "x" is the "unknown number".
</span>_______________________________________________________
Explanation:
______________________________________________________
Given:  
_________________________________________________________
"Two decreased by a half of a number is one-half<span> of the number" ; 

Let "x" represent the "unknown number" for which we wish to solve;

Write the expression as:
_________________________________________________
" </span>2 − (½)x = (½)x " .
_________________________________________________
Note:  Add "(½)x" to EACH SIDE of the equation:
_________________________________________________
2 − (½)x + (½)x = (½)x + (<span>½)</span>x ;

to get:
_________________________________________________
       →  2 = 1x ; 

       ↔  1x = 2 ;
 
       ↔ x = 2 .
_________________________________________________
Answer:  The number is:  " 2 " .
_________________________________________________
7 0
4 years ago
Which of these triangle pairs can be mapped to each other using have reflections?
KIM [24]

Answer:

Unfortunately on this image we are only able to see a portion of the problem, could you send a better photo, and i will solve imidiatly, thank you!!!!!

Step-by-step explanation:

3 0
3 years ago
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