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igomit [66]
3 years ago
13

Triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R

Mathematics
2 answers:
svlad2 [7]3 years ago
4 0

Answer:

PR

Step-by-step explanation:

Law of cosine expression for the triangle will be

q² = r² + p² - 2 (rp) cos Q

going by the equation r and p is given and Q is included then we can calculate q which corresponds to PR which faces or is subtended by angle Q. p correspond to QR and r correspond to PQ.

Mkey [24]3 years ago
4 0

Answer:

PR

Step-by-step explanation:

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What does the initial amount represent on the linear equations word problems?
galben [10]

Answer:

0

Step-by-step explanation:

The initial value or y-intercept is the output value when the input of a linear function is zero.

6 0
3 years ago
3 = logb(512)<br><img src="https://tex.z-dn.net/?f=%20log_%7Bb%7D%28512%29%20" id="TexFormula1" title=" log_{b}(512) " alt=" log
zzz [600]

Answer:

<h2>b = 8</h2>

Step-by-step explanation:

\text{Use}\ \log_ab=c\iff a^c=b,\ \text{for}\ a>0,\ b>0\ \wedge\ a\neq1\\\\Domain:b>0\ \wedge\ b\neq1\\\\\log_b(512)=3\iff b^3=512\to b=\sqrt[3]{512}\\\\\begin{array}{c|c}512&2\\256&2\\128&2\\64&2\\32&2\\16&2\\8&2\\4&2\\2&2\\1\end{array}\\\\512=2^9=2^{3\cdot3}=(2^3)^3=8^3\\\\\text{Therefore}\ b=\sqrt[3]{512}=\sqrt[3]{8^3}=8\in D

\text{Used:}\\\\(a^n)^m=a^{nm}\\\\\sqrt[n]{a^n}=a

6 0
3 years ago
Please answer<br> quick to!
mrs_skeptik [129]

Answer: C.)

Step-by-step explanation:

5 0
3 years ago
What is the square root of 9 over 25
GenaCL600 [577]
Sqrt(9)÷25= 0.12     I hope this helps!
6 0
4 years ago
Read 2 more answers
Ken is 6 feet tall and is walking away from a streetlight. The streetlight has its light bulb 14 feet above the ground, and Ken
AlekseyPX
Ken's distance is:  d(t)=1.7t

Ken's shadow is:

(14-6)/d(t)=14/s

8/d(t)=14/s

s=14d(t)/8

s=1.75d(t) and using the value for d(t) we have:

s=1.75(1.7t)

s=2.975t  and if you want it in terms of d, d=1.7t, t=d/1.7 so

s=2.975(d/1.7)

s=1.75d
5 0
3 years ago
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