Triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R
2 answers:
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Answer:
∠CFD = 60°
Step-by-step explanation:
Along line CE:
∠AFE + ∠AFB + ∠BFC = 180° (sum of angles on a straight line)
(7x + 4) + (8x + 6) + (6x + 2) = 180
collecting alike terms:
7x + 8x + 6x + 4 + 6 + 2 = 180
21x + 12 = 180
21x = 168
x = 8°
We could find the measure of CFD using:
a) Along line AD:
∠AFB + ∠BFC + ∠CFD = 180° (sum of angles on a straight line).
(8x + 6) + (6x + 2) + ∠CFD = 180
14x + 8 + ∠CFD = 180
∠CFD = `180 - (14x + 8)
∠CFD = 172 - 14x
b) ∠CFD = ∠AFE (vertical opposite angles are equal)
∠CFD = 7x + 4
To find value of ∠CFD, substitute x = 8
∠CFD = 7(8) + 4
∠CFD = 60°
