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2 years ago

Write the number in standard form. 600,000 + 30,000 + 2,000 + 700 +70

Mathematics

2 answers:

Basile [38]2 years ago

4 0

Standard form would be: 632,770
Hope it helps!!

slava [35]2 years ago

3 0

632,770 because you have 600,000 in your hundred thousands place than 30,000 in your ten thousands place than 2,000 in your thousands place than 700 in the hundreds place than 70 in your tens place

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If a shape is being dilated with a scale factor of 5 will be larger or smaller than original figure

Valentin [98]

Answer:

Larger

Step-by-step explanation:

It will Be larger because a factor lower then 5 will make the dilatetion become smaller

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2 years ago

Miguel Rodriguez borrowed $500 from his brother Julio to pay for books and tuition. He agreed to pay back in 6 months with simpl

dolphi86 [110]

he will pay $31 in interest after 6 months so after 6 months he will pay $531

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3 years ago

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

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2 years ago

What are the slopes ?

Viefleur [7K]

Answer:

11. is a slope of -7/2

12. is a slope of 4 :)

Step-by-step explanation:

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2 years ago

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Inga [223]

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and subtracting x from this eliminate the trailing decimal.

1000x - x = 4338.338338338… - 4.338338338…

999x = 4334

x = 4334/999

6 0

2 years ago