In this question, you would be simplifying.
Simplify:
(-x³- x) + (6x² + 6x - 7)
-x³- x + 6x² + 6x - 7
-x³ + 6x² + 5x - 7
You can't simplify any further, so your answer would be:
-x³ + 6x² + 5x - 7
Answer:
-x^3 + 6x^2 + 5x - 7
Answer:
The data provide strong evidence that young men weigh more on average than old men in the U.S
Step-by-step explanation:
Given :
The null hypothesis ; H0 : μ1 = μ2
The alternative hypothesis ; H1 : μ1 > μ2
T score = 5.3 ; Pvalue = < 0.0001
The decision region :
If Pvalue < α ; We reject the Null
If Pvalue > α ; We fail to reject the Null
When the α - level isn't stated, we usually assume a α - level of 5%
However, even at lower alpha level of 1% = 0.01 ;
The Pvalue < α
Hence, we can conclude that there is significant evidence that there is difference in the mean weight of young men and old men in the U.S
Answer:
x=62
y=45
Step-by-step explanation:
Complementary angles add to 90o
the other angle = x
the first angle = 3x - 4
x + 3x - 4 = 90
4x - 4 = 90
4x = 94
x = 94/4
x = 23.5
the first angle = 3*23.5 - 4 = 66.5
Answer:
Charmaine earns $60.90 for 6h for mowing and 1h for babysitting.
Step-by-step explanation:
We must write the data problems.
Charmaine = $8.80/h mowing
Charmaine = $8.10/h babysitting
How much will Charmaine earn for 6 h mowing and 1 h babysitting?
1 h mowing ....................... $8.80
6 h mowing ....................... $x
x = 6 h mowing * $8.80
x = $52,8
To find the total earn of Charmaine, we have to gather the earns from mowing and babysitting.
$52,8 (from mowing) + $8.10 (from babysitting) = $60.90
