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3 years ago

Find the 13th term of the geometric sequence 6, -30,150

Mathematics

1 answer:

sladkih [1.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

$a_1=6\\a_2=-30\\a_3=150\\\\\dfrac{a_2}{a_1}=\dfrac{-30}{6}=-5\quad\wedge\quad \dfrac{a_2}{a_2}=\dfrac{150}{-30}=-5\quad\implies\ \ q=-5\\\\\\a_n=a_1\cdot q^{n-1}\\\\a_{13}=a_1\cdot q^{12}=6\cdot(-5)^{12}=6\cdot244140625=1464843750$

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The statement that corrects the error in his table is:

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Read more about states of matter at:

brainly.com/question/18538345

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The graphs of f(x)=-2x and g(x)=(1/2)^x are shown. what are the solutions to thr equation -2x=(1/2)^x? select each correct answe

sineoko [7]

Answer:

Step-by-step explanation:

hello :

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