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ololo11 [35]
2 years ago
6

Find the 13th term of the geometric sequence 6, -30,150

Mathematics
1 answer:
sladkih [1.3K]2 years ago
6 0

Answer:

<h3>             a₁₃ = 1 464 843 750</h3>

Step-by-step explanation:

a_1=6\\a_2=-30\\a_3=150\\\\\dfrac{a_2}{a_1}=\dfrac{-30}{6}=-5\quad\wedge\quad \dfrac{a_2}{a_2}=\dfrac{150}{-30}=-5\quad\implies\ \ q=-5\\\\\\a_n=a_1\cdot q^{n-1}\\\\a_{13}=a_1\cdot q^{12}=6\cdot(-5)^{12}=6\cdot244140625=1464843750

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Hi there! :)

Answer:

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Step-by-step explanation:

Given:

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3 years ago
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Answer:

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Step-by-step explanation:

Hope this helps! Have a fantastic day and please mark brainliest

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The above highlights mean that:

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