Ask question

Ask question

All categories

3 years ago

10

The graphs of f(x)=-2x and g(x)=(1/2)^x are shown. what are the solutions to thr equation -2x=(1/2)^x? select each correct answe

r.
-2
-1
2
4

1 answer:

sineoko [7]3 years ago

4 0

Answer:

<h2>-2</h2>

Step-by-step explanation:

hello :

f(x)=-2x and g(x)=(1/2)^x

f(-2)=-2(-2) =4

g(-2)=(1/2)^-2 = 1/2^-2 = 2²=4

You might be interested in

A number has more tens than ones. the value of the ones digit is 8. what are the possible numbers?

natulia [17]

-----98 with any quantity of any digits before the 9 .

3 0

3 years ago

Read 2 more answers

Translate each algebraic expression to a verbal phrase

GaryK [48]

Answer:

1. A number decreased by seven.

2. A number increased by nine.

3. The product of six and a number, divided by eight.

4. The product of three and a number increased by five is equal to twenty.

5. The product of two and a number increased by eight is equal to twenty-three.

Step-by-step explanation:

1. x-7

A number decreased by seven.

2. y+9

A number increased by nine.

3. 6m/8

The product of six and a number, divided by eight.

4. 3y+5 =20

The product of three and a number increased by five is equal to twenty.

5. 2(x+8)= 23

The product of two and a number increased by eight is equal to twenty-three.

3 0

3 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle y = \frac{3}{2x^2}$ <u />

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

<u>Step 2: Differentiate</u>

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

<u>Step 3: Solve</u>

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

3 years ago

What is the general equation of a sine function with an amplitude of 6, a period of StartFraction pi Over 4 EndFraction, and a h

Katen [24]

Answer:

C: $y = 6 \sin (8(x-\frac{\pi}{2} ))$

Step-by-step explanation:

Amplitude is changed by multiplying the entire trig function by a number, by default the amplitude is 1, so multiplying by 6 is necessary; eliminate A and B

Horizontal shift is going through the x axis, so it must be subtracted from the x value. This is only seen in choice C of the remaining answers.

Calculating the period isn't necessary because we already found the right answer but in case you need it in the future; the period is by default 2pi, to get to pi/4, it had to be 8 times smaller, so multiplying x and translations on x by 8 will get you the correct period.

3 0

3 years ago

Read 2 more answers

An aircraft flying at an average speed of 770 km/h takes 15 hours to complete a journey. Find the time taken for the aircraft to

Hoochie [10]

We can solve it two ways, we´ll do it via physics:
We know that:
d=vt
d=770km/h*15h
d=11550km
Now at 660km/h:
t=d/v
t=11550km/660km/h
t=17,5h
Math way:
770km/h→15h
660km/h→x
So:
(770*15)/660=x
x=17,5h

8 0

3 years ago

Read 2 more answers