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Novay_Z [31]
3 years ago
10

The graphs of f(x)=-2x and g(x)=(1/2)^x are shown. what are the solutions to thr equation -2x=(1/2)^x? select each correct answe

r.
-2
-1
2
4
Mathematics
1 answer:
sineoko [7]3 years ago
4 0

Answer:

<h2>-2</h2>

Step-by-step explanation:

hello :

f(x)=-2x and g(x)=(1/2)^x

f(-2)=-2(-2) =4

g(-2)=(1/2)^-2 = 1/2^-2 = 2²=4

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He cost, in millions of dollars, of building a three-story high school in new york state was estimated to be c(x) = 2.1 + 0.12x
ratelena [41]

Given cost function is

c(x) = 2.1 + 0.12x - 0.0001x^2 (20 ≤ x ≤ 400)

where x is the number of thousands of square feet

total revenue will be $0.2 million dollars per thousand square feet

Revenue is 0.2 millions per thousand square feet. we know x is the number of thousand of square feet

So R(x) = 0.2x

We know Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = 0.2x - (2.1 + 0.12x - 0.0001x^2)

P(x) = 0.2x - 2.1 - 0.12x + 0.0001x^2)

combine like terms

P(x) =-2.1 + 0.08x + 0.0001x^2

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P(x) =0.0001x^2 + 0.08x - 2.1


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3 years ago
A local coupon mailer charges $11 for each of the first three lines of an ad, and $5 for each additional line. What is the price
Tema [17]
: $55

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Cost first 3 lines: $11 per line
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We are interested in 5-line ad, we place 3 lines or less, then we have to pay $11 per line in the ad.

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3 0
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Can someone help me with number 50?
timama [110]
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3 0
3 years ago
A is between C and D. True or false?
DanielleElmas [232]

Answer:

false

Step-by-step explanation:

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3 0
3 years ago
If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?
Diano4ka-milaya [45]

Answer:

x=8

\m\angle HFG= 80^\circ

Step-by-step explanation:

Given that:

Point H is interior of \angle EFG.

m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ

To find:

x = ?\\m\angle HFG = ?

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

m\angle EFG = m\angle EFH + m\angle HFG

Putting all the values given in above equation, we get:

(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}

m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}

8 0
3 years ago
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