Given:
3 kids
72 is the product of their ages.
There is a youngest child.
This means that all three are of different ages. We need to factor 72 into 3 integers.
Let us use prime factorization:
72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 = 9
9 ÷ 3 = 3
Prime factors are: 2 x 2 x 2 x 3 x 3 OR 2³ x 3²
3 ages.
eldest = 3³ = 9
middle = 2² = 4
youngest = 2¹ = 2
2 x 4 = 8
8 x 9 = 72
Answer:
The best estimate is 32 out of 32 times, she will be early to class
Step-by-step explanation:
The probability of being early is 99% = 99/100 = 0.99
So out of 32 classes, the best estimate for the number of times she will be early to class will be;
0.99 * 32 = 31.68
To the nearest integer = 32
Answer:
~181 containers filled completely, 6 eggs left over
Step-by-step explanation:
2178 ÷ 12 (a dozen, the number of eggs per container) = 181.5 containers
181 × 12 = 2,172 eggs
2,178 eggs - 2,172 = 6 eggs left over
Square root of 36y^3 = √36y^3
= 6√y3
=6∛y
