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ale4655 [162]
3 years ago
10

Its an edge question

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

a) The value of If(i)I  =  √2.

Step-by-step explanation:

Here the given function is f(x) = 1 -  x

To Find: If(i)I

First;y, let us find the value of f(i).

Substituting x  = i in f(x) , we get:

f(i)  = 1- i

Now, The modulus value of a function P = A + B is written as :

IPI = IA+BI = \sqrt{A^2 + B^2}

So, here calculating the value of If(i)I :

I1-iI   = \sqrt{(1)^2 + (-1)^2} = \sqrt{1+ (1)} = \sqrt {1+1} = \sqrt{2}\\\implies I1-iI  = \sqrt{2}

⇒ I1-1I = √2

or, If(i)I =√2

Hence, the value of If(i)I  for f(x) = 1 -x is√2.

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