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mylen [45]
3 years ago
11

The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the first, second,

and third places to go to the team members. In how many ways can the thirteen team entrants achieve first, second, and third places
Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

1716 ways

Step-by-step explanation:

Given that :

Number of entrants = 13

The number of ways of attaining first, second and third position :

The number of ways of attaining first ; only 1 person can be first ;

Using permutation :

nPr = n! ÷(n-r)!

13P1 = 13! ÷ 12! = 13

Second position :

We have 12 entrants left :

nPr = n! ÷(n-r)!

12P1 = 12! ÷ 11! = 12

Third position :

We have 11 entrants left :

nPr = n! ÷(n-r)!

11P1 = 11! ÷ 10! = 11

Hence, Number of ways = (13 * 12 * 11) = 1716 ways

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Likurg_2 [28]

Answer:

No ABC is not a triangle

Step-by-step explanation:

Perimeter = 22 cm

AB = 8 cm ; BC = 8 cm

AC = 22 - ( 8 + 8 ) = 6 cm

But all those sides doesn't follow Pythagorean Theorem(AB^2 + BC^2 = AC^2) ....because 8^2 + 8^2 isn't equal to 6^2 ......

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6 0
3 years ago
Help please <br> Right angle triangle
baherus [9]

Answer:

h ≈ 11.9

Step-by-step explanation:

Since the triangle is right we can use the cosine ratio to find h

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Multiply both sides by 13

13 × cos24° = h

⇒ h = 11.9 cm ( to 1 dec. place )

8 0
3 years ago
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Sergio [31]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Does someone know this? :)
kvv77 [185]

Answer:

Your answer would be

- 2/25 x^3a^3

Or vice versa with the variables

- 2/25 a^3x^3

TO solve it’s pretty simple if you do it correctly.

So with all the variables in the two multiples, you can find a way to combine them

So ignoring everything else you’d get

a^2x * x^2a

You we can see the difference,

theres a^2 and a

Whilst there is also x^2 and x

Now we can combine them

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Now we can do the normal multipacation with the fraction

2/5 * - 1/5 which is -2/25

Now combine

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Drupady [299]

Answer:

25

Step-by-step explanation:

Cross multipy

4h = 100

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3 years ago
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