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mylen [45]
3 years ago
11

The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the first, second,

and third places to go to the team members. In how many ways can the thirteen team entrants achieve first, second, and third places
Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

1716 ways

Step-by-step explanation:

Given that :

Number of entrants = 13

The number of ways of attaining first, second and third position :

The number of ways of attaining first ; only 1 person can be first ;

Using permutation :

nPr = n! ÷(n-r)!

13P1 = 13! ÷ 12! = 13

Second position :

We have 12 entrants left :

nPr = n! ÷(n-r)!

12P1 = 12! ÷ 11! = 12

Third position :

We have 11 entrants left :

nPr = n! ÷(n-r)!

11P1 = 11! ÷ 10! = 11

Hence, Number of ways = (13 * 12 * 11) = 1716 ways

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The drink recipe uses 6 cups of water and 2 cups of apple juice.
ladessa [460]

Answer:

25%

Step-by-step explanation:

2/8 = 1/4 = 0.25 = 25%

6 0
3 years ago
Which graph represents the function f(x)=0.2x+3?
g100num [7]

Answer:

The top right

Step-by-step explanation:

The y intercept is = 0.2^(0) + 3 = 1+3 = 4

Now let considered some point

Let x = 3

0.2^(3) + 3 = 3.008

Let x = 10000

0.2^(10000) + 3 = 3.00032

As we can see, it approaching 3 so the top right is correct

3 0
3 years ago
What is Three to the power of negative three
Rom4ik [11]

Answer:

0.04

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How many integers between 100 and 999 (inclusive) have distinct digits
daser333 [38]

Answer:

648

Step-by-step explanation:

Running this in Python, with the code as follows,

import math

cur_numbers = [0] * 3

num = 0

for i in range(100, 1000):

   cur_numbers[2] = i % 10

   i = math.floor(i/10)

   cur_numbers[1] = i % 10

   i = math.floor(i/10)

   cur_numbers[0] = i % 10

   if(len(set(cur_numbers)) == 3):

       num += 1

       print(cur_numbers)

       

print(num), we get 648 as our answer.

Another way to solve this is as follows:

There are 9 possibilities for the hundreds digit (1-9). Then, there are 10 possibilities for the tens digit, but we subtract 1 because it can't be the 1 same digit as the hundreds digit. For the ones digit, there are 10 possibilities, but we subtract 1 because it can't be the same as the hundreds digit and another 1 because it can't be the same as the tens digit. Multiplying these out, we have

9 possibilities for the hundreds digit x 9 possibilities for the tens digit x 8 possibilities for the ones digit  = 648

5 0
3 years ago
32i-4+2=6-42i-3 help
Dmitrij [34]
15i would be your best answer
8 0
3 years ago
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