Rhombus ABCD with vertices A(2, 6), B(6, 7), C(5, 3), and D(1, 2): 180°
1 answer:
Answer:
Step-by-step explanation:
Rule for the rotation of a point 180° about the origin is,
(x, y) → (-x, -y)
Therefore, images of the points after the rotation of 180° will be,
A(2, 6) → A'(-2, -6)
B(6, 7) → B'(-6, -7)
C(5, 3) → C'(-5, -3)
D(1, 2) → D'(-1, -2)
Now we can plot these points on the graph as attached.
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Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if
here;
Thus;
∴
Hence, we can conclude that r(t) and s(t) are parallel.
Answer:
Can someone please help me with this question?
Step-by-step explanation:
Answer:
(3, 0)
Step-by-step explanation:
Given the inequality y > -2x + 3 and y ≤ x - 2
The graph of the inequalities are plotted using the geogebra graphing online calculator.
The portion of the graph that is shaded with dark blue, represents the portion that supports the equation.
All the ordered pair points given in the question are also labelled in the graph.
From the graph we can see that only point (3, 0) falls in the area that supports the equation. Hence (3, 0) makes both inequalities true.
