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Annette [7]
3 years ago
13

A rectangular prism with a volume of 5 cubic units is filled with cubes with side lengths of 1/3 unit. How many 1/3 unit cubes d

ocs it take to fill the prism? ​
NVM I GOT IT
Mathematics
1 answer:
ozzi3 years ago
4 0
What’s ever it it good for you
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Someone help me with this
Alenkasestr [34]

Answer:

70°

Step-by-step explanation:

ABC is the center angle that sees the arc and is twice as angle ADC so the measure of ABC is e × 35 = 70

3 0
4 years ago
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Find the solution for 6x+3y=3 3x-y=4​
Mariana [72]
I think the answer is 7x
5 0
3 years ago
Use the quadratic formula to find the solutions to the
nadezda [96]

Answer:

D

Step-by-step explanation:

The quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

where a is the coefficient of x^2, b being the coefficient of x and c being the constant.

Plug in the values:

\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}

\frac{5\pm\sqrt{-15} }{4}

Since \sqrt{-15} =\sqrt{-1} \sqrt{15} =i \sqrt{15}

The answer is:

\frac{5\pm i \sqrt{15} }{4}

6 0
3 years ago
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A bag with 8 marbles has 8 yellow marbles. A marble is chosen from the bag at random. What is the probability that it is yellow?
lara [203]

Answer:

8/8 or just 1 whole will be yellow

7 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
Evgesh-ka [11]

Answer:

approximately 8.5

Step-by-step explanation:

So you can use the distance formula: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\ which is derived from the Pythagorean theorem because normally x2-x1 would kind of give the distance length between x2 and x1 except sometimes it would be negative which wouldn't make much sense right? but it doesn't matter because it's being squared so the value ultimately becomes positive, and the same thing goes for the y-value. the distance between x2 - x1 really represents the base and y2-y1 represents the height and then adding them together gives the hypotenuse squared which is why you take the square root over the entire thing to find the distance, since the hypotenuse is the shortest distance between two points

Now all you have to do is plug the values in to get

\sqrt{(-7 - (-4))^2 + (-8 - 0)^2}\\\sqrt{(-3)^2 + (-8)^2}\\\sqrt{9 + 64}\\\sqrt{73}\\distance \approx 8.5

5 0
2 years ago
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