<h3><u>The system of linear equations that represents the situation is:</u></h3>
a + b = 28
16a + 10b = 400
<h3><u>20 scented candles and 8 unscented candles were sold</u></h3>
<em><u>Solution:</u></em>
Let "a" be the number of scented candles sold
Let "b" be the number of unscented candles sold
From given,
Cost of 1 scented candles = $ 16
Cost of 1 unscented candles = $ 10
<em><u>The shop sells 28 candles today</u></em>
Therefore,
a + b = 28
b = 28 - a ------- eqn 1
<em><u>The shop sells 28 candles today and makes $400</u></em>
Therefore,
number of scented candles sold x Cost of 1 scented candle + number of unscented candles sold x Cost of 1 unscented candles = 400
16a + 10b = 400 ------ eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
16a + 10(28 - a) = 400
16a + 280 - 10a = 400
6a = 400 - 280
6a = 120
a = 20
<em><u>Substitute a = 20 in eqn 1</u></em>
b = 28 - 20
b = 8
Thus 20 scented candles and 8 unscented candles were sold
9514 1404 393
Answer:
f(x) = x³ -5x² +2x +8
Step-by-step explanation:
If the function has a zero of p, then it has a factor of (x-p). The polynomial of least degree will only have factors corresponding to the given zeros:
f(x) = (x -(-1))(x -2)(x -4)
= (x +1)(x -2)(x -4)
= (x² -x -2)(x -4)
f(x) = x³ -5x² +2x +8
Answer:
9 miles
Step-by-step explanation:
A 6+3 is nine
Answer:
3 inches
Step-by-step explanation:
If the dog chews off 4 inches every day, you first have to multiply the inches by the number of days, which in this case is 3 x 4, which equals 12. In 3 days, he chewed off 12 of the original 15 inches, leaving only 3 inches left.
Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
