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Shtirlitz [24]
2 years ago
9

A local diner uses 4 2/3 pounds of meat to make five hamburgers. How much meat is used to make one hamburger?

Mathematics
1 answer:
hodyreva [135]2 years ago
8 0

Answer:14/15 pounds of meat

Step-by-step explanation:

<h3>SO, 4 2/3=14/3</h3><h3>5 HAMBURGERS ARE MADE BY USING 14/3 POUNDS OF MEAT</h3><h3>1 HAMBURGER IS MADE BY USING 14/3×1/5 OR,14/15 POUNDS OF MEAT.</h3><h3>BASICALLY THE ANSWER IS:14/15 pounds of meat is used to make one hamburger.</h3>

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3 years ago
Elton is a candle maker. Each 15 cm long candle he makes burns evenly for 6 hours if Elton makes a 45 cm long candle, how long w
tatuchka [14]

The candle would burn for 18 hours.

45 / 15 = 3

If the candle is three times longer than normal, it will burn three times longer than normal.

3 x 6 = 18


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3 years ago
Plz reanswer it If (x+4): (3x+1) is the duplicate ratio of 3:4 find the value of x.​
Rzqust [24]
Answer: x = 13/5

Explanation:

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3 0
3 years ago
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Which of the following is equal to the fraction below?
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6 0
3 years ago
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A research study investigated differences between male and female students. Based on the study results, we can assume the popula
garri49 [273]

Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = 0.5.
  • Sample of 100, hence n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2 = \frac{X - 3.5}{0.05}

X - 3.5 = -0.1

X = 3.4

Z = 2:

Z = \frac{X - \mu}{s}

2 = \frac{X - 3.5}{0.05}

X - 3.5 = 0.1

X = 3.6

The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

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2 years ago
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